Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
216 comments Page 7 of 22.
Krishna said:
2 decades ago
4*3*7 is wrong right one is 4*12 k
Vidhya said:
2 decades ago
Why we have to take the difference of those two numbers?
Sita said:
1 decade ago
I'm not clear with any of the above explanation. Can anyone tell me clearly.
Mini said:
1 decade ago
Why they took the differences of given 3 numbers and then calculated the H.C.F.
Why didn't they simply calculate the H.C.F OF GIVEN 3 NUMBERS.
Why didn't they simply calculate the H.C.F OF GIVEN 3 NUMBERS.
Mysterious said:
1 decade ago
@Mini and all friends
If it was just asked to find the HCF of 43,91,183 then simply the Division method or Factorization method had been applied.
But here it is stated that "so as to leave the same remainder in each case", that's why the difference of the numbers is calculated.
If it was just asked to find the HCF of 43,91,183 then simply the Division method or Factorization method had been applied.
But here it is stated that "so as to leave the same remainder in each case", that's why the difference of the numbers is calculated.
Sandeep.ch said:
1 decade ago
Please tell me which is the perfect explanation.
Abhishek said:
1 decade ago
@Prashant: thanks for best explanation.
Ajit said:
1 decade ago
Thanks prashant for best explanation.
Nadhirsha said:
1 decade ago
Well done Prashant.
Samir said:
1 decade ago
Which is the highest five digit number which is equally divisible by 60, 80, and 90 and how to arrive this answer ?
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