IndiaBIX

Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
Problems on H.C.F and L.C.M
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
4
7
9
13
Answer: Option
Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

     = H.C.F. of 48, 92 and 140 = 4.

Discussion:
212 comments Page 6 of 22.
Komal said:   1 decade ago
The difference is used to get the common factors between two nos. it will eliminate the uncommon factors.

And at-last we have only to pick up the highest common factor...
you can try with an example for 30 and 10.

factors of (30) = 5,2,3
factors of (10) = 5,2
factors of (30-10) = 5,2
Habib said:   1 decade ago
The difference is taken to analyze the pattern. Amongst the numbers !

Ie each difference tells us that these numbers are multiples of 4 and have the same remainder because all numbers can be divided by 4.

Hence you get 4.
JAYALALITHA said:   1 decade ago
WHY WE HAVE TO TAKE DIFFERENCE OF THOSE TWO NUMBERS
Prathyusha said:   1 decade ago
SMART WAY OF SOLVING BY @SHWETHA
Yuva kumar said:   1 decade ago
Dear Sir/madam please expain I could not understand.
R. Ahmad said:   1 decade ago
Why it is used two times 183 nos Explain?
Fil said:   1 decade ago
If you mult 4*3*7 its coming 84 how 4 will be the greatest no please explain me.
Krishna said:   1 decade ago
4*3*7 is wrong right one is 4*12 k
Vidhya said:   1 decade ago
Why we have to take the difference of those two numbers?
Sita said:   1 decade ago
I'm not clear with any of the above explanation. Can anyone tell me clearly.
Post your comments here:

Your comments will be displayed after verification.

Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers