Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
210 comments Page 6 of 21.
Surbhi swaraj said:
1 decade ago
Is there any trick to solve this problem?
Heena said:
1 decade ago
Here take the difference between the numbers then start dividing.
48/2, 92/2, 140/2
Then
48/2=2*2*2*2*3
92/2=2*2*23
140/2=2*2*35
So HCF is [nothing but the highest common factor].
So HCFis 2*2=4.
48/2, 92/2, 140/2
Then
48/2=2*2*2*2*3
92/2=2*2*23
140/2=2*2*35
So HCF is [nothing but the highest common factor].
So HCFis 2*2=4.
Lovely said:
1 decade ago
Hey prashant your explanation is too good. Thanks.
Is there more short method to do solve this.
Is there more short method to do solve this.
Aadhilakshmi said:
1 decade ago
Thanks for the clear explanation prasanth.
Parthiban said:
1 decade ago
It is very simple
consider
43,91,183 are the 3 numbers
first ,
find the diff between them
91-43=48;
183-91=92;
183-43=140;
let divide the 48,92,140,by 2
we have
48=2*2*2*2*3
92=2*2*23
140=2*2*149
here common factor is 2*2
so
answer is 4
consider
43,91,183 are the 3 numbers
first ,
find the diff between them
91-43=48;
183-91=92;
183-43=140;
let divide the 48,92,140,by 2
we have
48=2*2*2*2*3
92=2*2*23
140=2*2*149
here common factor is 2*2
so
answer is 4
Mayank said:
1 decade ago
4*22-gives rem 3.
4*10-gives rem3.
4*45-also gives rem 3.
All three numbers have equal rem 3 satisfies condition given in number. Hence ans is 4.
4*10-gives rem3.
4*45-also gives rem 3.
All three numbers have equal rem 3 satisfies condition given in number. Hence ans is 4.
Cathy said:
1 decade ago
How do you know we are to find the h.C.F ?
I seem to be getting so confused.
I seem to be getting so confused.
Karthick said:
1 decade ago
@Cathy.
The keyword is greatest or largest- if you find these words, we are required to find HCF. If in case you find least or lowest in the problem, we need to find LCM.
The keyword is greatest or largest- if you find these words, we are required to find HCF. If in case you find least or lowest in the problem, we need to find LCM.
Ankur jindal said:
1 decade ago
If three nos as in this case is 43, 91 and 183 are given then to find HCF the shortest solution is take the diff:
1) 91 - 43 = 48 (4*3*7).
2) 183 - 91 = 92 (4*23).
3) 183 - 43 = 140 (4*7*5).
Thus the HCF is 4.
1) 91 - 43 = 48 (4*3*7).
2) 183 - 91 = 92 (4*23).
3) 183 - 43 = 140 (4*7*5).
Thus the HCF is 4.
Merry said:
1 decade ago
When pratibhan said the common factor is 2 ok this is write but why she multiple two no of 2 whyn't three no of 2 means the result is 8.
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