Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
4
7
9
13
Answer: Option
Explanation:

Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)

     = H.C.F. of 48, 92 and 140 = 4.

Discussion:
210 comments Page 12 of 21.

Shwetha said:   1 decade ago
Simply divide each number by 4 the remainder is same for all so the answer is 4.

Fil said:   1 decade ago
If you mult 4*3*7 its coming 84 how 4 will be the greatest no please explain me.

Furqan said:   1 decade ago
What is different between HCF & LCM?
And what is the meaning HCF & LCM?

Somanath said:   1 decade ago
Find the highest number which divides 25 and 29 equally leaving 5 in each case.

Prem said:   1 decade ago
I am unable to understand this problem. Can anyone explain all steps involved?

Raje said:   1 decade ago
Simply way is divide 43, 81 and 183 by 4 we get the same remainder 3 for all.

Cathy said:   1 decade ago
How do you know we are to find the h.C.F ?

I seem to be getting so confused.

Sita said:   1 decade ago
I'm not clear with any of the above explanation. Can anyone tell me clearly.

Senthmaizhan said:   9 years ago
All this explanation are not clear to me. Please explain it in a simple way.

Mrunmay said:   8 years ago
Why numbers are being subtracted? I still have a doubt. Please explain me.


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