Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
214 comments Page 11 of 22.
Niveditaa singh said:
1 decade ago
Is this only method to solve this?
If it can be solve by another way then please explain.
If it can be solve by another way then please explain.
Dileep gowda said:
1 decade ago
Yes your right @Sowjanya. But @Prasanth is almost right I think you need more information.
Mayur Jagtap said:
2 years ago
4 * 10 = 40 +3.
4 * 22 = 88 + 3.
4 * 45 = 180 + 3.
Remainder is same 3.
Hence number is 4.
4 * 22 = 88 + 3.
4 * 45 = 180 + 3.
Remainder is same 3.
Hence number is 4.
(88)
Pinku said:
7 years ago
43/4 = 3(remainder).
91/4 = 3(remainder).
183/4 = 3(remainder).
91/4 = 3(remainder).
183/4 = 3(remainder).
Saumya tyagi said:
1 decade ago
Well I also cannot understand the correct logic of solving this question please explain.
Arsh said:
9 years ago
Here, the remainder is unknown that is why we have only chance to find their difference.
Vamsi said:
6 years ago
48 = 4 * 12
92 = 4 * 23
140 = 4 * 35.
1,2,3,5 prime numbers so 4 is the correct answer.
92 = 4 * 23
140 = 4 * 35.
1,2,3,5 prime numbers so 4 is the correct answer.
(1)
Anomie said:
5 years ago
P is called the divisor & not dividend.
(Divisor x quotient) + remainder= dividend.
(Divisor x quotient) + remainder= dividend.
(1)
Anirudh rai said:
2 decades ago
Is this the only way to this type of problem?
If yes then would you please explain it.
If yes then would you please explain it.
Sowjanya said:
1 decade ago
In @Prasanth answer, p is the divisor not dividend and the analysis of sum is correct.
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