Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 1)
1.
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Answer: Option
Explanation:
Required number = H.C.F. of (91 - 43), (183 - 91) and (183 - 43)
= H.C.F. of 48, 92 and 140 = 4.
Discussion:
210 comments Page 13 of 21.
Hema said:
1 decade ago
Why we have to take the difference of the numbers can you please explain?
Bisht Ashish said:
9 years ago
@Prashant.
In your explanation, 'p' must be a Divisor, not the Dividend.
In your explanation, 'p' must be a Divisor, not the Dividend.
Brianna said:
9 years ago
I don't understand I'm only eleven, please someone help me to get this.
Hind said:
1 decade ago
I go with same method as shweta and dhanasekar has said in the forum.
Umar said:
10 years ago
How to solve the same question if remainder is not same in each case?
STUTI said:
8 years ago
I understood the sum now.
Given explanations was good. Thankyou all.
Given explanations was good. Thankyou all.
Rony said:
1 decade ago
HCF of two numbers is 12, their sum is 72, then the two numbers are?
Abhishek Ray said:
1 decade ago
Kindly revert back with logically, how this problem was processed?
Sruthi said:
1 decade ago
Why we have to take the difference of the numbers please explain?
Nagu said:
2 decades ago
Why they took difference between those nos.
Please explain me.
Please explain me.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers