Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
77 comments Page 7 of 8.
Ravi said:
1 decade ago
@ vani
Its false statement that LCM is the the greater no.
We know as a*b = lcm*hcf
Here 4107 = lcm*37
lcm = 111 or (3*37)
so a*b = 37*3*37
or a*b = (37*3)*37
or a*b = 37*(3*37)
So greater no. is 3*37=111
Its false statement that LCM is the the greater no.
We know as a*b = lcm*hcf
Here 4107 = lcm*37
lcm = 111 or (3*37)
so a*b = 37*3*37
or a*b = (37*3)*37
or a*b = 37*(3*37)
So greater no. is 3*37=111
Vani said:
1 decade ago
Can LCM always be the greatest no.?
Muthusamy said:
1 decade ago
Thanks raju and thulasi.
111 said:
1 decade ago
Thanks anand
Thulsi said:
1 decade ago
Best method by verification.
Divide 4107 by 37 we get 111.
Divide 4107 by 37 we get 111.
Sachin said:
1 decade ago
Best method is to use the co primes as it in the given explanation.
4107/37=111, which is not the correct solution.
4107/37=111, which is not the correct solution.
Priya said:
1 decade ago
This will work on co-primes. If two numbers are not coprimes then how should we find out ?
Rahul said:
1 decade ago
Thanks Pannu.
Anand said:
1 decade ago
Simply multiply the value 37*111=4107
Jyoti said:
2 decades ago
Simply divide the product with H.C.F
i.e 4107/37=111
i.e 4107/37=111
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