Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
101
107
111
185
Answer: Option
Explanation:

Let the numbers be 37a and 37b.

Then, 37a x 37b = 4107

ab = 3.

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).

Greater number = 111.

Discussion:
76 comments Page 6 of 8.

Aman Kaushik said:   1 decade ago
Just a very simple method.

Product of the two number/ HCF.
4107/37 = 111.

Vijesh said:   1 decade ago
SIMPLE METHOD:

PRODUCT OF THE TWO NUMBERS = LCM*HCF.
4107 = 37*LCM.
LCM = 111.

MAHESH said:   1 decade ago
X*Y = 4107.

X*37 = 4107.

X = 4107/37.

X = 111.

Bipin said:   1 decade ago
Simply as we know:

LCM x HCF = product of co-prime or a x b.

Given that,

Product of two nos = 4107
HCF = 37
LCM = ?

Finally we can put the value on above formula,
LCM*HCF = product.
LCM = 4107/37.
LCM = 111 Answer.

Roy said:   1 decade ago
What is co-prime nos?

Sushma said:   1 decade ago
Its simple let a * b = 4107 now 37 is common in both a and b so 37*some number(x)=4107 so solve this 37*x=4107 so 4107/37 =111.

Sugandh said:   1 decade ago
Let we have two numbers 2 and 6...
now product of these two numbers=12
hcf(2 and 6)=2
lcm=6
now we hav 2 find d greater numbr that is 6..how it comes..it is simply d lcm...
it means we hav to find out the lcm....so somply divide the product f two numbers by their hcf to get the lcm;,,,,

12/2=6 =greatest number

Hhmnmb said:   1 decade ago
Thanks Anand

Vinay said:   1 decade ago
It is not essential that LCM will always be greater number
@ ravi
your explanation are good

Ravi said:   1 decade ago
@ vani
Its false statement that LCM is the the greater no.
We know as a*b = lcm*hcf
Here 4107 = lcm*37
lcm = 111 or (3*37)
so a*b = 37*3*37
or a*b = (37*3)*37
or a*b = 37*(3*37)
So greater no. is 3*37=111


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