Aptitude - Problems on H.C.F and L.C.M - Discussion

Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
101
107
111
185
Answer: Option
Explanation:

Let the numbers be 37a and 37b.

Then, 37a x 37b = 4107

ab = 3.

Now, co-primes with product 3 are (1, 3).

So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).

Greater number = 111.

Discussion:
76 comments Page 5 of 8.

Kajal said:   10 years ago
How we come to know that in this question we have to find LCM, in the question we have to find the greater number, reply as soon as possible?

David said:   9 years ago
H.C.F * L.C.M.

Product of that two numbers is this equality only in case of co-prime numbers or all other numbers also.

Can anyone please confirm me.

Raushan said:   9 years ago
In the any condition you can take, it is not only for co-prime. It will work for all.

And two numbers are said to be co-prime if the HCF is 1.

Sangeetha said:   9 years ago
How will we decide 111 is the largest number?
(1)

Surya said:   9 years ago
Properties of LCM & HCF.

We know, product of 2 numbers = (LCM of 2 numbers) * (HCF of 2 numbers).
So, 4107 = LCm of 2 numbers * 37,
Then, We get 111.

Ramesh M said:   9 years ago
Same doubt for me @Sangeetha.

Please can anyone help us.

Anirudh said:   9 years ago
1250 is the product of x and y. What is the HCF of x and y?

Solve and explain the solution.

OM SHANKAR PRASAD said:   9 years ago
@Anirudh.

Because we can make pair of (10*125) , (50*25), (250*5), (2*625), (1*1250), so HCF is varying, so I think more data need.

Asif said:   8 years ago
How we come to know that in this question we have to find LCM, in the question we have to find the greater number? please.

Priya.E said:   8 years ago
Thnks @Pannu.


Post your comments here:

Your comments will be displayed after verification.