Aptitude - Problems on H.C.F and L.C.M - Discussion
Discussion Forum : Problems on H.C.F and L.C.M - General Questions (Q.No. 6)
6.
The product of two numbers is 4107. If the H.C.F. of these numbers is 37, then the greater number is:
Answer: Option
Explanation:
Let the numbers be 37a and 37b.
Then, 37a x 37b = 4107
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
Greater number = 111.
Discussion:
77 comments Page 8 of 8.
Omprakash said:
4 years ago
Thanks, everyone.
(6)
MANJULADEVI K said:
3 years ago
The product of 2 number is 4107.
The HCF of these number is 37.
4107= 37 * a
4107/37 = a
Answer is 111.
The HCF of these number is 37.
4107= 37 * a
4107/37 = a
Answer is 111.
(86)
Vaibhavi said:
3 years ago
Let the numbers be 37a × 37b
Then, 37a × 37b = 4107.
37ab = 4107/37,
37ab = 111,
ab = 111/37.
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
The Greater number = 111.
Then, 37a × 37b = 4107.
37ab = 4107/37,
37ab = 111,
ab = 111/37.
ab = 3.
Now, co-primes with product 3 are (1, 3).
So, the required numbers are (37 x 1, 37 x 3) i.e., (37, 111).
The Greater number = 111.
(28)
Bijip said:
2 years ago
Why we will take co-prime here? Please explain me.
(13)
Frio said:
2 years ago
Thanks all for the explanation.
(4)
Sonu Gurjar said:
12 months ago
Formula:
4107 = 37 * lcm,
Lcm = 4107/37 = 111.
4107 = 37 * lcm,
Lcm = 4107/37 = 111.
(21)
Harika said:
2 months ago
4107 product of 37.
This is divisible by 111.
So, the answer is 111.
This is divisible by 111.
So, the answer is 111.
(1)
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