Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 12)
12.
Ayesha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
2 years
4 years
6 years
8 years
Answer: Option
Explanation:

Mother's age when Ayesha's brother was born = 36 years.

Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.

Required difference = (42 - 36) years = 6 years.

Discussion:
44 comments Page 2 of 5.

Armaniac said:   8 years ago
Fathers age - Mothers age -----> 38-36 = 2,
brothers age ---> (x-4),
so,
(x-4)=2,
x = 6.
(2)

Syed Rasheed said:   3 months ago
Simple,

When Ayesha was born, the father's age is 38.
When his brother 4 years younger than her sister mother's age is 36.
Then 4 years of the father's increasing,
So, 42 - 36,
6 yrs.
(1)

Farah said:   1 decade ago
It's simple.

Ayesha father was 38yrs when she was born.

And ayesha Mother was 36yrs after 4 years when her brother born.

Therefore, Ayesha mother was 32 years when SHE was born (36-4).

ANSWER: 38-32 = 6 years of difference between age of HER Parents.
(1)

Rohit yadav said:   8 years ago
Take Ayesha age at a time to find the difference.

Ayesha age=0 then father age=38.
Ayesha's brother, who is younger than him by 4 years.
When Ayesha'brother born his mother age =36 that time Ayesha age is 4 year.
So back to four years that time Ayesha age is 0 and his mother age is 32.
Now, find the difference of father and mother age because of now Ayesha age become=0.
To find differene of age either Ayesha age for his brother age must be =0<<<<<.
(1)

Apurv porwal said:   7 years ago
Ayesha's age = 0
Father's age = 38
Mother's age = 36

Ayesha is 4 years
4 years after =0
Mother's age =32.
(1)

Bharathi said:   9 years ago
Ayesha's mother was 36 years old when her brother four years younger to her means when Ayesha born her mother's age 36 - 4 = 32 years.

And when she born her father's age 38.
So, 38 - 32 = 6 years.

Sumit Kumar said:   9 years ago
Let, Ayesha Age was X year when she born.

That time father age was 38 yrs.

Now father age X+38 and as well as Mother's age X+36.

Brother is younger than Ayesha was 4 yrs

So, X-4 .

Now Difference = (X+38) - (X+36) = X-4

X+38-X-36 = X-4

2 = X-4

So,

X = 6 yrs.

Pramod kuamr said:   10 years ago
I don't get it. How can we assume that Ayesha's brother was born when she was 4 ? all the thing is given was difference between them is 4 years. Anybody please explain.

Pravallika said:   1 decade ago
Ayesha father mother 0 38 not mentioned.

After 4 years brother born to Ayesha.

0+4, 38+4, 36 years (given).

Now difference between fathers and mothers age.

= 42-36.

= 6 years.

Debjani Nandy said:   10 years ago
Let Ayesha's age be denoted by A, her father's age by AF, her mother's age by AM and her brother's age by AB respectively.

Then acc to all the givens in the question,

AF - A = 38 --- (1).
A - AB = 4 --- (2).
AM - AB = 36 --- (3).

Now,

AM - AB = 36 [from Equation (3)].

AM - (A-4) = 36 [from Equation (2)].

AM - (AF - 38 - 4) = 36 [from Equation(1)].

AM - AF + 38 + 4 = 36.

AF - AM = (38 + 34) - 36.

AF - AM = 42 - 36.

=> 6 (ANS).


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