Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 12)
12.
Ayesha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
Answer: Option
Explanation:
Mother's age when Ayesha's brother was born = 36 years.
Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.
Required difference = (42 - 36) years = 6 years.
Discussion:
44 comments Page 5 of 5.
Siddharth said:
1 decade ago
Suppose Ayesha was born in year 1990.
Then acc. to question, her brother who is 4 years younger to her
Should have born in 1994.
Now her father's age in 1990: 38.
Therefore, her father's age in 1994: 38 + 4 = 42.
Thus difference between ages of parents in year 1994:
42(father's age) - 36(mother's age) = 6 years.
Then acc. to question, her brother who is 4 years younger to her
Should have born in 1994.
Now her father's age in 1990: 38.
Therefore, her father's age in 1994: 38 + 4 = 42.
Thus difference between ages of parents in year 1994:
42(father's age) - 36(mother's age) = 6 years.
D-basu said:
1 decade ago
When Aisa born his father was 38. After 4 year his brother was born, so father become 38+4=42.
Mother age when brother was born = 36.
So the difference when brother born 42-36 = 6 years.
Mother age when brother was born = 36.
So the difference when brother born 42-36 = 6 years.
Shubham said:
1 decade ago
Here condition is given that @Ayesha is smaller than his brother so I think answer is 2.
John said:
1 decade ago
See the @Virender rajput answer it is clear. In question they didn't give any pull stop(.) and comma(,) if you see care fully they gave the mother age is when her brother born means it is 36 but her father age at Ayesha's born so we have to add 4 years to father age.
I hope you guys got it.
I hope you guys got it.
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