Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
326 comments Page 7 of 33.
Manmeet said:
6 years ago
The answer should be 2.5.
Pratheeksha said:
6 years ago
How 5/2? Can anyone explain.
Stark said:
6 years ago
I got the answer as two and one-fifth times.
Priya said:
6 years ago
Why we are adding the 16 in the step 4x+16/x+16, sir.
4x+16/x+16 how to get this step. Please explain sir.
4x+16/x+16 how to get this step. Please explain sir.
Akshay said:
6 years ago
How 48/24 came?
Please tell me.
Please tell me.
Dharanisree said:
6 years ago
How 5/2?
Varun said:
6 years ago
Why we have to add x=8 ? I think we have to substitute the the value of x. Can anyone explain?
Janmaijay said:
6 years ago
How two and a half times can be written like 5/2 it must be 2/5?
Waqas Raza said:
7 years ago
Couldn't understand (4x+16/ x+16) = 2? what's the logic behind this?
Ashok said:
7 years ago
How you got ratio (4x+16)/(x+16)?
Can you explain the last step of ratio?
Can you explain the last step of ratio?
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers