Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
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(4x + 8) = | 5 | (x + 8) |
2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
(x + 16) | 24 |
Discussion:
319 comments Page 31 of 32.
Naveen said:
2 years ago
F:S
3:1 *3 = 9p:3p
5:2 *2 = 10p:4p
1p = 8years.
5 * 8 + 8 : 2 * 8 + 8.
48 : 24.
While comparing both father is 2 times more than the son.
3:1 *3 = 9p:3p
5:2 *2 = 10p:4p
1p = 8years.
5 * 8 + 8 : 2 * 8 + 8.
48 : 24.
While comparing both father is 2 times more than the son.
(16)
Villasnjsjs said:
2 years ago
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
2(4x + 8) = 5(x + 8).
8x + 16 = 5x + 40.
3x = 24.
x = 8.
Hence, required ratio = (4x + 16) = 48 = 2.
Then (x + 16)24.
2(4x + 8) = 5(x + 8).
8x + 16 = 5x + 40.
3x = 24.
x = 8.
Hence, required ratio = (4x + 16) = 48 = 2.
Then (x + 16)24.
(11)
Ganesh Lokhande said:
2 years ago
Why 5/2 is used? Please explain to me.
(29)
Mani said:
2 years ago
In the question, son's age is 2 (1/2) age.
So, 2x1/2 is 5/2fraction form.
So, 2x1/2 is 5/2fraction form.
(18)
Abhishek Zatakiya said:
1 year ago
Let son age = x.
Father age = y.
X + 3x = y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8.
5x+40 = 2y+16.
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 years,
Son age 24 & father age 48.
Therefore 2 times.
Father age = y.
X + 3x = y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8.
5x+40 = 2y+16.
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 years,
Son age 24 & father age 48.
Therefore 2 times.
(31)
Unknown said:
1 year ago
How ratio be calculated in this question? Please explain to me.
(3)
Rajdip Kumar Dora said:
1 year ago
How it's 16 years? Can anyone please explain?
(5)
Vaibhav said:
1 year ago
@All.
This question is a tricky one, as it states Father's age is three times more than Ronit's age. The "times" would imply F=3R but it also has a "more" statement. Meaning that Father's age is what adds to 3 times Ronit's age to Ronit's age, which means.
F = 3R+R.
This question is a tricky one, as it states Father's age is three times more than Ronit's age. The "times" would imply F=3R but it also has a "more" statement. Meaning that Father's age is what adds to 3 times Ronit's age to Ronit's age, which means.
F = 3R+R.
(48)
Mohit patil said:
1 year ago
How come 16 here? Anyone, Explain to me.
(8)
Bharathviswa said:
1 year ago
It's 16 because we assume the son's age is x and the father is x + 3x = 4x.
We equate it and find the son's present age is 8.
So, we need to find 8+8 years, that's how it became 16.
We equate it and find the son's present age is 8.
So, we need to find 8+8 years, that's how it became 16.
(8)
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