Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 28 of 32.
Shubham Londhe said:
5 years ago
It's only said his age would be 2.5 times of son's age after 8 years.
So only 2.5 * X seems logical. Why 2.5(X+8)? Explain it.
So only 2.5 * X seems logical. Why 2.5(X+8)? Explain it.
Gauri_ said:
5 years ago
Why 16 is added? Explain in detail.
Akash said:
5 years ago
@Gauri.
Because 8 Years+ 8 Years =16 Years.
Because 8 Years+ 8 Years =16 Years.
Ganesh said:
5 years ago
I think 3 times more than X means = 3X And three times less than X means = X/3.
Vamsidhar said:
5 years ago
How come 4x? Explain.
Madhav said:
4 years ago
Let fathers age be f and son age be s
given
f= 3s+s = 4s.
f + 8 = 2 * (s+8) = 5/2 (s+8).
So 4s +8 =5/2 (s+8)we get s=8, also f= 4*8 =32.
Let x times.
Given,
(f+16) = x(s+16)substitute f and s value,
we get x=2.
given
f= 3s+s = 4s.
f + 8 = 2 * (s+8) = 5/2 (s+8).
So 4s +8 =5/2 (s+8)we get s=8, also f= 4*8 =32.
Let x times.
Given,
(f+16) = x(s+16)substitute f and s value,
we get x=2.
Sree said:
4 years ago
Let Rohit age=X.
By condition:Fathers age=X + 3X,
After 8 yrs,
Fathers age=5/2(X+8).
So, 4x+8=5/2(x+8).
8x+16=5x+40.
X=8.
Sub x=8 in 5/2(x+8).
Ans:40.
After 8 yrs,
40+8=48.
Sons age present=8,
After 16 yrs, age=24,
24*2=48.
So, the answer is 3 times.
Thank you
By condition:Fathers age=X + 3X,
After 8 yrs,
Fathers age=5/2(X+8).
So, 4x+8=5/2(x+8).
8x+16=5x+40.
X=8.
Sub x=8 in 5/2(x+8).
Ans:40.
After 8 yrs,
40+8=48.
Sons age present=8,
After 16 yrs, age=24,
24*2=48.
So, the answer is 3 times.
Thank you
Gora4663 said:
4 years ago
Let son age = x
Father age = y.
X + 3x =y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8
5x+40 = 2y+16
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 year,
Son age 24 & father age 48.
Therefore 2 times.
Father age = y.
X + 3x =y( acc to 1st statemnt) ---> eq1
5/2(X+8) = y+8
5x+40 = 2y+16
5x-2y=-24 ---> eq2.
Solve eq 1 and 2 we get;
X=8 then y = 24,
After 16 year,
Son age 24 & father age 48.
Therefore 2 times.
Manoj said:
4 years ago
How (4x+16) / (x+16) is = 48/24? Explain please.
(2)
Sunil said:
4 years ago
The right answer is 3.
At first it is;
1 : 4.
then;
2 : 5.
Here difference after 8 years is 1.
1 part = 8 years.
Again we increase 8 years;
3 : 6.
At first it is;
1 : 4.
then;
2 : 5.
Here difference after 8 years is 1.
1 part = 8 years.
Again we increase 8 years;
3 : 6.
(3)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers