Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
326 comments Page 28 of 33.
Stella said:
1 decade ago
Thank you friends for your explanations.
Arjun said:
1 decade ago
@Cosmicguypradeep
Let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x }(i agree this part)
after 8 years,
4x+8=x+8....equation (1)( doubt here q1: how X=4X that is how father age is equal to son age )
Let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x }(i agree this part)
after 8 years,
4x+8=x+8....equation (1)( doubt here q1: how X=4X that is how father age is equal to son age )
Cosmicguypradeep said:
1 decade ago
Simple
let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x
after 8 years,
4x+8=x+8....equation (1)
age will be 2 and half years i.e 2 1/2 = 5/2,
4x+8=5/2(x+8)
==> 8x+16=5x+40
==> x=8
after further 8 years;
4x+8+8=?(x+8+8)
4x+16=?(X+16)
==> ?=4x+16/x+16...equation (2)
==> substitute x=8 in eqution (2),
u will get ?=2
let the age of the son be "x"
father is aged 3 times more than his son so x+3x=4x
after 8 years,
4x+8=x+8....equation (1)
age will be 2 and half years i.e 2 1/2 = 5/2,
4x+8=5/2(x+8)
==> 8x+16=5x+40
==> x=8
after further 8 years;
4x+8+8=?(x+8+8)
4x+16=?(X+16)
==> ?=4x+16/x+16...equation (2)
==> substitute x=8 in eqution (2),
u will get ?=2
Rohan said:
1 decade ago
Answer to 5/2(x+8) ...in example its is written that After 8 years, he would be two and a half times of Ronit's age
So two and a half is 2 1/2, now 2x2 is 4 and 4+1 is 5 so its 5/2..
So two and a half is 2 1/2, now 2x2 is 4 and 4+1 is 5 so its 5/2..
Savitha said:
1 decade ago
We already add 8 years....to get the x value then Why we add 16 yrs in second step.
Gautam Negi said:
1 decade ago
Thanks a lot guys.
Preethi said:
1 decade ago
Thank you vaisu & uttam for your explainations.
Ezhil Arasan SCAD CET said:
1 decade ago
Guess whatz the wrong here:
1st father age is 24 and Rohit age is 8...
atter 8 years: father age is shd b 24+8=32 and Rohit age is 8+8=16...
But in sum itz given after 8 years his age is 2.5 times>then Rohit age... But here 32 nd 16 two times only greater... Why?
1st father age is 24 and Rohit age is 8...
atter 8 years: father age is shd b 24+8=32 and Rohit age is 8+8=16...
But in sum itz given after 8 years his age is 2.5 times>then Rohit age... But here 32 nd 16 two times only greater... Why?
Amrutha said:
1 decade ago
Rohit age is x and his father age is 3x ofter 8 years rohit age is 5/2(x+8) and his father age is 3x+8 therefore
3x+8=5/2(x+8)
6x+16=5x+40
x=24
Rohit age is 24 then his father age is 72 year ofter 8 years
It becomes 32 and 80 it is exactly 2 1/2 times of rohit age so answer is 2 times.
3x+8=5/2(x+8)
6x+16=5x+40
x=24
Rohit age is 24 then his father age is 72 year ofter 8 years
It becomes 32 and 80 it is exactly 2 1/2 times of rohit age so answer is 2 times.
Minal said:
1 decade ago
Hi,
See two and half means 2*1/2
So 2*2+1 = 5/2.
See two and half means 2*1/2
So 2*2+1 = 5/2.
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