Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
319 comments Page 26 of 32.

Jagadeesh said:   1 decade ago
Thanks vaishu I understood your explanation clearly.

Manoj said:   1 decade ago
@durgesh. Your explanation is very good. Nice one.

Shaila said:   1 decade ago
Ravee too good explanation.

Karan said:   1 decade ago
@Ravee superb.

Durgesh said:   1 decade ago
Hi friends,

Let son"s age is =1 then father age=4
which means ratio between father to son= 4 :1 (say f: s)........[1]
after 8 years this ratio = 2.5 : 1 ( f :s)
= 5:2...................[2]

but one thing is clear that difference betwwen father age and son age will always be same.


In eq. [1] difference is 3 and in [2] is 3 as it shuld be.

Now take a look at fther age .............it was 4 and after 8 years it is 5 ...it means in our values
I
n the ratio 1=8,
so ........................5=40(father age after 8 years)
and.......................2=16(son age after 8 years )

Hence after further 8 years later father age =40+8 =48 years and
................. son age = 16+8= 24

So ratio = 48:24
=2:1

Shweta chaubey said:   1 decade ago
Son present age is =x
than father's present age is=more than 3 times of son age
=x+3x
According to the question,
after 8 years..
x+8=x+3x+8
x+8=4x+8
and father will be 5/2 greater than son
5/2(x+8)=4x+8
5x+40=8x+16
3x=24
x=8
ratio after 8 years
4x+8+8/x+8+8=6/3=2

Ravee said:   1 decade ago
Hi Sharaddha here sum explansn to your doubt.

As you said Father's age is three times then son's age.

Here x or 1x both are same, I think you done this way.

"X", to this three times as 1x, 2x, 3x.

This way u'll get 3x, but we know X and 1X are same so.

To X (or 1X both are same) it is three times as 2x, 3x, 4x.

Now the F's age is X+3X=4X.

RAVEE said:   1 decade ago
Hi frndz my solution takes much lenghthy, but have tried to give a clear explanation

Let Father=F & Rohith=R
consider R's age as "X"
Now F's age will three times morethan R's age, so it'll be X+3X=4X
Now in 2011 F's age is 4X and R's age is X, but after 8 years say 2019 what is the F's age?
4X+8 and R's age X+8 (add 8 to F' and R)
As mentioned in the statement the age of F's is two and half(2+1/2) times ,so it will be 5/2.

STEP1:
Now on LHS side it is F's age
4X+8
and RHs it is R's age X+8 multiple of 5/2 as
4X+8=x+8(5/2)
=> 2(4X+8)=5(X+8)
=> 8X+16=5X+40
=> 8X-5X=40-16
=> 3X=24
=> X=24/3
Therefore X=8

STEP2:
again after 8 years
(4X+8+8)=(X+8+8)
=>4x+16=x+16
=>4x+16/x+16=?
we have X=8

So,
4*8+16/8+16=?
32+16/24=?
48/24=?
the ans is "2"

Hope u got it..
(1)

Subrata Hazra said:   1 decade ago
It is very much clear in the question first line that father is aged three times more than his son Ronit.

So simple is that if his sons age -x , then his age is x+3x = 4x

Shraddha said:   1 decade ago
As in question, fathers age is three times more than son's age. If we take sons age as x than father's age wll 3x how that 4x?


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