Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
![]() |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
322 comments Page 26 of 33.
Parveen said:
1 decade ago
Is thare any shortcut to solve this in seconds.
Manohar said:
1 decade ago
Try this way now the ratio is
4: 1
8 (4x2)=8 8-5=3x=8(5-2)
5 :2 5x1)=5 x=8
32 8 after 8 yrs 40 16 further 8 yrs 48 24 2;1
4: 1
8 (4x2)=8 8-5=3x=8(5-2)
5 :2 5x1)=5 x=8
32 8 after 8 yrs 40 16 further 8 yrs 48 24 2;1
Chandu said:
1 decade ago
THANKQ. Vaishu for your explanation.
Jagadeesh said:
1 decade ago
Thanks vaishu I understood your explanation clearly.
Manoj said:
1 decade ago
@durgesh. Your explanation is very good. Nice one.
Shaila said:
1 decade ago
Ravee too good explanation.
Karan said:
1 decade ago
@Ravee superb.
Durgesh said:
1 decade ago
Hi friends,
Let son"s age is =1 then father age=4
which means ratio between father to son= 4 :1 (say f: s)........[1]
after 8 years this ratio = 2.5 : 1 ( f :s)
= 5:2...................[2]
but one thing is clear that difference betwwen father age and son age will always be same.
In eq. [1] difference is 3 and in [2] is 3 as it shuld be.
Now take a look at fther age .............it was 4 and after 8 years it is 5 ...it means in our values
I
n the ratio 1=8,
so ........................5=40(father age after 8 years)
and.......................2=16(son age after 8 years )
Hence after further 8 years later father age =40+8 =48 years and
................. son age = 16+8= 24
So ratio = 48:24
=2:1
Let son"s age is =1 then father age=4
which means ratio between father to son= 4 :1 (say f: s)........[1]
after 8 years this ratio = 2.5 : 1 ( f :s)
= 5:2...................[2]
but one thing is clear that difference betwwen father age and son age will always be same.
In eq. [1] difference is 3 and in [2] is 3 as it shuld be.
Now take a look at fther age .............it was 4 and after 8 years it is 5 ...it means in our values
I
n the ratio 1=8,
so ........................5=40(father age after 8 years)
and.......................2=16(son age after 8 years )
Hence after further 8 years later father age =40+8 =48 years and
................. son age = 16+8= 24
So ratio = 48:24
=2:1
Shweta chaubey said:
1 decade ago
Son present age is =x
than father's present age is=more than 3 times of son age
=x+3x
According to the question,
after 8 years..
x+8=x+3x+8
x+8=4x+8
and father will be 5/2 greater than son
5/2(x+8)=4x+8
5x+40=8x+16
3x=24
x=8
ratio after 8 years
4x+8+8/x+8+8=6/3=2
than father's present age is=more than 3 times of son age
=x+3x
According to the question,
after 8 years..
x+8=x+3x+8
x+8=4x+8
and father will be 5/2 greater than son
5/2(x+8)=4x+8
5x+40=8x+16
3x=24
x=8
ratio after 8 years
4x+8+8/x+8+8=6/3=2
Ravee said:
1 decade ago
Hi Sharaddha here sum explansn to your doubt.
As you said Father's age is three times then son's age.
Here x or 1x both are same, I think you done this way.
"X", to this three times as 1x, 2x, 3x.
This way u'll get 3x, but we know X and 1X are same so.
To X (or 1X both are same) it is three times as 2x, 3x, 4x.
Now the F's age is X+3X=4X.
As you said Father's age is three times then son's age.
Here x or 1x both are same, I think you done this way.
"X", to this three times as 1x, 2x, 3x.
This way u'll get 3x, but we know X and 1X are same so.
To X (or 1X both are same) it is three times as 2x, 3x, 4x.
Now the F's age is X+3X=4X.
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