Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
 |
(4x + 8) = | 5 | (x + 8) |
| 2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
| Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
| (x + 16) | 24 |
Discussion:
319 comments Page 20 of 32.
Husain SR. said:
9 years ago
Here, 2 and a half means 2.5.
So, 5/2 = 2.5.
Example: 3.5 means 7/2. Hope you get it.
So, 5/2 = 2.5.
Example: 3.5 means 7/2. Hope you get it.
Ammulu said:
9 years ago
Thanks @Vaishu. You explained it very clearly. :).
Ismail said:
9 years ago
Your clarification is very simple, Thanks @Vaishu.
Vignesh said:
9 years ago
I didn't understand the last step of the explanation. Please clarify me.
Sonu said:
9 years ago
How is it 4x? I didn't get it please tell me clearly.
Selva said:
9 years ago
if Father is aged three times more than his son Ronit means, 3x + x = 4x then After 8 years, he would be two and a half times of Ronit's age.
In that above 'he' represent Ronit's father which means
(3x + 8) = 5/2(x + 8) right?
Then, how it will be (4x + 8) = 5/2(x + 8)?
In that above 'he' represent Ronit's father which means
(3x + 8) = 5/2(x + 8) right?
Then, how it will be (4x + 8) = 5/2(x + 8)?
Kishan said:
9 years ago
@Maqsood nice explanation. Thank you.
Arpitha said:
9 years ago
It's so simple!
The value of x is ''8'' so 4 x is (4(8) + 16)/(8 + 16) and you get 48/24 = 2.
The value of x is ''8'' so 4 x is (4(8) + 16)/(8 + 16) and you get 48/24 = 2.
Kavana said:
9 years ago
A is 2 years older than C and B is 2 years younger than C. The ratio of A's 6 years ago and B's 8 years ago is 6 : 5. Find C's present age.
COOLCALM said:
9 years ago
Father F and Rohit R.
So, F = 3R + R = 4R.
After 8 years,
F + 8 = 2 1/2 (R + 8) means, F + 8 = 5/2 (R + 8).
So, 2(F + 8) = 5R + 40,
2(4R + 8) = 5R + 40,
8R + 16 = 5R + 40,
3R = 24,
R = 8.
Rohit's present age = 8 years.
After 16 years of present day (8 + 8).
Ratio would be F + 16/ R + 16.
So, 4R + 16/R + 16,
4(8) + 16/8 + 16 = 48/24 = 2.
So, F = 3R + R = 4R.
After 8 years,
F + 8 = 2 1/2 (R + 8) means, F + 8 = 5/2 (R + 8).
So, 2(F + 8) = 5R + 40,
2(4R + 8) = 5R + 40,
8R + 16 = 5R + 40,
3R = 24,
R = 8.
Rohit's present age = 8 years.
After 16 years of present day (8 + 8).
Ratio would be F + 16/ R + 16.
So, 4R + 16/R + 16,
4(8) + 16/8 + 16 = 48/24 = 2.
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