Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
319 comments Page 2 of 32.

Srikanth said:   1 decade ago
5/2 (x+8) ? Can anybody please explain me why this expression has used?.

Jwala said:   1 decade ago
(4x+8) is father's age.

2 and half is written as 5/2...i.e., (2 1/2 = ((2*2) +1)/2 => 5/2) (mixed fraction is converted into proper fraction).

(x+8) is ronit's age.

Sheela said:   1 decade ago
Its 3x + x = 4x. Because its 3 times more not only 3 times.

Thara said:   1 decade ago
I can't understand this question how 5/2 came?

Meera said:   1 decade ago
Hi, Please explain the last step of ratio.

Preethi said:   1 decade ago
How you got ratio (4x+16) / (x+16) ?

Ratikant said:   1 decade ago
Please explain the last step of ratio.

Arun said:   1 decade ago
4x+16,here 4x represents father's age and 16 refers years 8year and further 8 years

Nandish said:   1 decade ago
(4x + 8) = 5 (x + 8)
2


8x + 16 = 5x + 40

how this 16 came

Shanmu said:   1 decade ago
How you got ratio (4x+16) / (x+16) ?
can u explain the last step of ratio.


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