Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
Answer: Option
Explanation:
Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.
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(4x + 8) = | 5 | (x + 8) |
2 |
8x + 16 = 5x + 40
3x = 24
x = 8.
Hence, required ratio = | (4x + 16) | = | 48 | = 2. |
(x + 16) | 24 |
Discussion:
319 comments Page 17 of 32.
Magesh said:
1 decade ago
I am so confused, after I did not get the answer.
Please anyone explain this problem clearly.
Please anyone explain this problem clearly.
Arpitha said:
9 years ago
It's so simple!
The value of x is ''8'' so 4 x is (4(8) + 16)/(8 + 16) and you get 48/24 = 2.
The value of x is ''8'' so 4 x is (4(8) + 16)/(8 + 16) and you get 48/24 = 2.
Raj said:
9 years ago
I can't understand this problem the second step is very confusing.
Someone help me to get it.
Someone help me to get it.
Husain SR. said:
9 years ago
Here, 2 and a half means 2.5.
So, 5/2 = 2.5.
Example: 3.5 means 7/2. Hope you get it.
So, 5/2 = 2.5.
Example: 3.5 means 7/2. Hope you get it.
Jaz said:
1 decade ago
@vaishu so, x+3x+8=x+8 this step am nt getting ..
(4x+8)=5/2(x+8) dis also...
(4x+8)=5/2(x+8) dis also...
Yash Anand said:
10 years ago
Can anybody tell me the shortest trick to solve this question? I mean in less than a min.
Godwin said:
1 decade ago
It is clearly mentioned two and half times. Therefore 2and 1/2.
i.e., (2*2+1) /2 = 5/2.
i.e., (2*2+1) /2 = 5/2.
Kasinath@Hyd said:
1 decade ago
2 and 1/2 == 5/2.
Since given "of Ronit's age", therefore multiply 2/5 to Ronit's age.
Since given "of Ronit's age", therefore multiply 2/5 to Ronit's age.
Manu said:
1 decade ago
I want details answer for 4x+16/x+16 and how did we get answer 48/24 please. Reply me.
Kavya said:
1 decade ago
I want details answer for 4x+16/x+16 and how did we get answer 48/24 please. Reply me.
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