Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 1)
1.
Father is aged three times more than his son Ronit. After 8 years, he would be two and a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's age?
2 times
1 times
2
3 times
4
3 times
Answer: Option
Explanation:

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5 (x + 8)
2

8x + 16 = 5x + 40

3x = 24

x = 8.

Hence, required ratio = (4x + 16) = 48 = 2.
(x + 16) 24

Discussion:
319 comments Page 15 of 32.

Anuj rojlove said:   1 decade ago
Consider son's age as 'x'.

So they have said,
Father is aged three times more than his son.

As per the statement, x+3x.
After 8 years, he would be 2 and a half times of his son.

So, x+3x+8 = x+8.
4x+8 = x+8.
(4x+8) = 5/2(x+8).

We get, 8x+16 = 5x+40 => 3x = 24.
x = 8.

After further 8 years,

So add 8 to the equation 4x+8+8 = x+8+8.
4x+16 = x+16.

So the ratio is, (4x+16)/(x+16) = 48/24.
=> 2 years.

Got it friends. Its simple?

Abhi said:   1 decade ago
Let Ronit's age = x.

So father's age will be (x+3x), (Let suppose you have sister who is 1 year younger than you then after 20 year your age will be 21 (Your sister age + 20 yr) = your age. So same in this question father age will be x+3x.

Now after 8 years mean rule no.2 (If x is current age then n year later age will be (x+n)).

Father's age will be (4x+8) and Ronit's age will be (x+8).

Now come to question that after 8 years father's age will be 5/2 times of Ronit's age.

So F age = 5/2 times of Ronit's age.

4x+8 = 5/2(x+8).

So by this we get x = 8.

Now we have to find after 8 year.

= 4x+8+8 = y(x+8+8).

So by solving this y = 2.

Thank you :).

Dhanu said:   1 decade ago
Any other short way to solve this question?

Hassan said:   1 decade ago
How can such a question be solved with in one minute?

Sowndariya said:   1 decade ago
Please explain the concept of solving this problem using shortcut method.

Sreeranga said:   1 decade ago
(4x + 8) = 2.5(x + 8).

4x + 8 = 2.5x + 20 and equation multiplied by 2.

Kasinath@Hyd said:   1 decade ago
2 and 1/2 == 5/2.

Since given "of Ronit's age", therefore multiply 2/5 to Ronit's age.

Naresh said:   1 decade ago
I think answer is 2.2 times.

x = son Ronit's age now.

3x = father's age now <--- father is 3 times son.

x + 8 = Ronit's age in 8 years.

3x + 8 = father's age in 8 years.

3x + 8 = 2.5 (x + 8) <--- after 8 years, father is 2.5 times son.

3x + 8 = 2.5x + 20 <--- used distributive property.

0.5x = 12 <--- subtracted 2.5x and 8 from each side.

x = 24 <--- divided each side by 0.5.

3x = 72 <--- substituted 24, in for x, into 3x.

Son Ronit is 24 now & father is 72 now.

Son Ronit will be 32 in 8 years & father will be 80 in 8 years.

Son Ronit will be 40 after further 8 years & father will be 88 after further 8 years.

Father will be 2.2 times son after further 8 years.

Fuhar said:   1 decade ago
The last step is easy but division sign gone somewhere else. Fathers age is 4X + 8 + 8 (here 8 + 8 are the years later) now divide this with sons age which is x. But after 8 + 8 years it would be x + 8 + 8 as we got x value substitute in the both numerator and denominator there you go you get as 48/24 and we taking in ratio forms as options are given in ratio like two times the son age etc.

Aafreen Rah said:   1 decade ago
How it is 4x?

Father's age is three times more than his son's age means. We can say (3x+x) or (3x+2x)...

Why we take it as (x+3x)?


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