Aptitude - Problems on Ages - Discussion

Father's age is 3x + x = 4x.
After putting 4x in the equation of 4x + 8 = 5/2(x + 8), then I got 8.

Further, I found that son's age is 8 and father's age is 32 because F = 4x.
Later I made an equation F's age + 8 = Son's age + 8 * y (i.e. F + 8 = 8 + 8 * y). I can't find the solution.

Please help me out.

Why can't be father' age (x + 3)?

Why it should be taken as (x + 3x)?

Very helpful to practise the problems. Thankyou all.

Let us assume Ronit age is 10 years, Father age is 3 times of Ronit age, so 10*3 = 30 years.

After 8 years Ronit age will 18 years father age will be 2.5 times of son age, so 2.5*18 = 45 years.

After 8 years father age would be 45 + 8 = 53 years and Ronit age would be 26 years.
So, 53/26 = 2.03.
Answer is 2 times.

How this 5/2 got?

5/2(x+8).

The ans is simple at present 2 1/2 +3=5/2 and present age is x and after 8 years +8 so (x+8).

Let the present age of Rohit be 'x' years and the present age of the father be 'y' years. As per the question father is aged three times more than his son hence, y = x+3x = 4x.

Therefore present age of father is y = 4x.

Given that after 8 years, he would be two and half times of Rohit's age.

Therefore,

y+8 = 5/2(x+8).
4x+8 = 5/2(x+8) {since y = 4x}.
2(4x+8) = 5(x+8).
8x+16 = 5x+40.
8x-5x+16-40 = 0.
3x-24 = 0 => 3x = 24 => x = 24/3 = 8.
x=8,

After 8 years,

y+8 = x+8.
4x+8 = x+8 {since y = 4x}.

After further 8 years, 'k' times would be the Rohit's age.

Therefore,

4x+8+8 = k (x+8+8).
4x+16 = k (x+16).
k = (4x+16) / (x+16).
k = (4.8+16) / (8+16).
k = 48/24.
k = 2.

Therefore 2 times would he be Rohit's age.

Please explain.

Father is aged three times more than his son Ronit.

Then why father age = x, and Ronit age is = x?

Why not father age = x? And son Ronit age = y.

Why will we add 8 + 8?

@Aishu.

Answer for your question:

http://www.meritanswers.com/questions/calculate-ram-present-age/17229-1-1