Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 8)
8.
The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:
12 years
14 years
18 years
20 years
Answer: Option
Explanation:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 6 = 5(x - 6)

54 - x = 5x - 30

6x = 84

x = 14.

Son's age after 6 years = (x+ 6) = 20 years..

Discussion:
71 comments Page 3 of 8.

Ashok said:   1 decade ago
Take father age = x.
Son age = y.

Sum of father+son = 60.
x+y = 60 eq(i).

6 yrs ago father age is 5 times the age of son.

x-6 = 5(y-6).
x-6 = 5y-30.
x = 5y-30+6.
x = 5y-24.

Sub x value in eq(i).
5y-24+y = 60.
6y = 60+24 = 84.
y = 14.

Then 6 yrs after the son age = 14+6 = 20 years.

Pravin Garodi said:   9 years ago
Consider son present age is X and father present age is Y.

X + Y = 60 consider this is first equation,

6 year ago father age is,
(Y - 6) = 5(X - 6),
5(X - 6) = Y - 6,
5X - Y = 24 this is second equation.

After solving 1 and 2 equation,
X = 14,
After 6 year son age is 14 + 6 = 20.

Abhi said:   5 years ago
@Amit.

You have already added 6 to bring question in present (x+6) & (5x+6). Now the outcome of this solution is 8yr right. This 8yr must be present age of son we have to add 6 to know future age hence, 8+6=14.

How have you added 8+6+6? I didn't understand please reply.
(2)

Manoj verma said:   1 decade ago
Suppose son's age=x father's age=y x+y=60 y-6=5(x-6) 60-x-6=5x-30 6x=84 x=14 after 6 years son's age=20

Somya khare said:   10 years ago
Son = x.
Father = y.

Then, x+y = 60.....(1).

6 years ago.

(y-6) = 5(x-6).

That is y-6 = 5x-30.

Therefore at present age we have y-6+6 = 5x-30+6.

That is, y = 5x-24.

From (1).

x+5x-24 = 60.
6x = 84.
x = 14.

Therefore after 6 years sons age will be.

14+6 = 20.

Bhanu said:   1 year ago
Let the father's age be x years and son's age be y years.
x + y = 60-->eqn 1
6 years ago.
x - 6 = 5(y-6)
x - 5y = -24--> eqn 2

By solving equations 1 and 2, we get
y = 14.

Son's age after 6 years = 14 + 6,
= 20 years.
(24)

Muhammad Umair Kabir said:   1 decade ago
Let 'F' be the Father's Age and 'S' be the Son's Age.

According to situation:

F+S = 60 EQ ---- 1
F-6 = 5(S-6) ,
Which is F-6 = 5S-30 EQ ---- 2

F = 5S -24 EQ ---- 3
Put this in EQ 1

5S - 24 + S = 60
6S = 84
S = 14

After 6 Years Sons age will be S = 14 + 6 = 20

Vijay Anand said:   1 decade ago
@Priya.

Your logic is correct but you have to subtract 12 from 60. You have subtracted 6 for sons age and for fathers age you have to subtract another 6 know so it will be 60-12 = 48 not 54.

If you want me to explain precisely means please let me know.

Haider said:   8 years ago
We can solve it by this method.

The sum of the ages =60
six years ago
we will subtract 12 years, 6 year each,
then sum would be 48.
divide by 6, bco s they are in the ratio of 1:5.
8 : 40 would be the answer,
Add 12 years to 8 and we get 20.

Imran Ali Korai said:   1 decade ago
Present age of son = x.
Present age of father = 5x.

6 years ago.

Son's age = x + 6.
Father's age = 5x + 6.

Sum of their ages.

X+6+5x+6 = 60.
6x = 48.
X = 8.

Son's age = x+6 = 14.

After Six Year's
14+6 = 20.

Hence 20 is correct answer.


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