Aptitude - Problems on Ages - Discussion

Some time it good to solve question without any quick formula.

Thanks Mickey.

Thanks to all. Now I got some idea.

Let f be the father's age and x be the son's age.

10 years ago.

f-10 = 3(x-10)
f = 3x-30+10
f = 3x-20 -----------(1)

10 years hence

f+10 = 2(x+10)
f = 2x+20-10
f = 2x+10 -----------------(2)

From 1 & 2

2x+10 = 3x-20
x = 30;
f=2*30 +10 ----from 2
f= 70;

Ratio is 7:3

Only 7:3 is viable when plugged in

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[ (x + 10) + 10].

How it is possible for adding 10 two times?

(3x + 10) + 10 = 2[ (x + 10) + 10]. Why we multiply right hand side of eq by 2 instead of left. As father age is twice so why we multiply son's age eq. Please explain?

Two emps talking each other , emp1 says to emp2 your age is two times more then me , emp2 exactly, emp1 says but 2 years back your experience twice time of my age, then what is present experience of emp2?

Given, father's age(x) = 3(y)son's age.

y = x/3.

Original equation is, 10 years ago x-10 = 3(y-10).

= 3(x/3-10).....(A).

Given, after 10 years father's age(x) = 2(y)son's age.

y = x/2.

Original equation is, after 10 years x+10 = 2(y+10).

= 2(x/2+10).........(B).

Equating (A) & (B) for present ages, 3(x/3-10) = 2(x/2+10).

x = 80.

y = 40.

These are the ages after 10 years.

Hence, for present ages remove 10 years from both 70:30 or 7:3.

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x + 10) + 10 = 2[(x + 10) + 10].

3x + 20 = 2x + 40.
x = 20.

Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.

Whats meaning of 10 years hence?