Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 15)
15.
The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. The ratio of their present ages is:
Answer: Option
Explanation:
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
3x + 20 = 2x + 40
x = 20.
Required ratio = (3x + 10) : (x + 10) = 70 : 30 = 7 : 3.
Discussion:
77 comments Page 2 of 8.
Manta said:
1 decade ago
Manish your method is looking very easy. But from where 20 has come?
Ramu said:
1 decade ago
Father's age is three years more than three times the son's age.After three years, father's age will be ten years more than twice the son's age. What is the father's present age.
Ramachandran said:
1 decade ago
@Ramu:
Now Assume Father age is x and Son age is y
According to first statement : Father's age is three years more than three times the son's age
x=3y+3
So x-3y=3 --->1
According to second statement : After three years, father's age will be ten years more than twice the son's age
x+3=2(y+3)+10
x-2y=13 ---->2
substitute 1 & 2:
x=33
y=10
So father's present age is 33.
Thank you god bless you all.
Now Assume Father age is x and Son age is y
According to first statement : Father's age is three years more than three times the son's age
x=3y+3
So x-3y=3 --->1
According to second statement : After three years, father's age will be ten years more than twice the son's age
x+3=2(y+3)+10
x-2y=13 ---->2
substitute 1 & 2:
x=33
y=10
So father's present age is 33.
Thank you god bless you all.
Manish said:
1 decade ago
VERY TRICKY!!!!!!
Suren said:
1 decade ago
Thanks nagu.
Mihir said:
1 decade ago
Can anybody tell the answer to this question?
In 1996, Raju age was equal to the numbers formed by the last two digits of his birth year. This was same for his grandfather also. Find the difference between their ages.
In 1996, Raju age was equal to the numbers formed by the last two digits of his birth year. This was same for his grandfather also. Find the difference between their ages.
Mickey said:
1 decade ago
Present ages be
father = x
son = y
10 years ago,
father = x-10
son = y-10
a/q
(x-10)= 3(y-10)..........1
10 years hence,
father = x+10
son = y+10
a/q
(x+10)= 2(y+10).......2
We get x=70, y=30.
father = x
son = y
10 years ago,
father = x-10
son = y-10
a/q
(x-10)= 3(y-10)..........1
10 years hence,
father = x+10
son = y+10
a/q
(x+10)= 2(y+10).......2
We get x=70, y=30.
Devendra said:
1 decade ago
All the trick are good but Malic trick is so, esy but one confusion here X=20 mens ago(back 10 year) &Hence(after 10yer) so.. 10+10 X=20.............
(3x+10):(x+10)=7:3........... Just put the value of X=20......
(3x+10):(x+10)=7:3........... Just put the value of X=20......
Vic said:
1 decade ago
TO SOLVE BOTH THE EQUATIONS
3X+10=2X-10 WHERE X=20
SO PUT THE X VALUE IN PLACES OF X
WILL PRODUCE THE RATIO
70:30 i.e=7:3
3X+10=2X-10 WHERE X=20
SO PUT THE X VALUE IN PLACES OF X
WILL PRODUCE THE RATIO
70:30 i.e=7:3
Anu said:
1 decade ago
Can anybody tell me how to find the ratio?
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