Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 4)
4.
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
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Answer: Option
Explanation:

Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.

(2x + 2) + 2x + x = 27

5x = 25

x = 5.

Hence, B's age = 2x = 10 years.

Discussion:
79 comments Page 4 of 8.

JANAKIRAM said:   5 years ago
A = B+2
B = 2C = >C=B/2
A + B + C = 27.

Substitute A & C values in above equation
B + 2 + B + B/2 = 27.
5B/2 = 25.
B = 10.
(2)

Sahas said:   6 years ago
a = two years more than b+2.
b = twice on c 2x.
Assume c = x.

b+2+2x+x.
Substitute b.
2x+2+2x+x=5x.
5x= 27-2.
x=5.
b = 2*5 = 10.
(3)

RAJU RONGPI said:   2 years ago
A= 2+B ---> 1
B=2C --->2.
A+B+C = 27
2 + B + 2C+ B/2 = 27.
2 + B + 2.B/2+B/2 = 27.
2B + B/2 = 25
4B + B = 50,
Then, B = 10.
(15)

Jatinder s said:   1 decade ago
A=B+2....1 given
B=2C .......2 given
from statement 2 : C=B/2
total is 27
therefor
A+B+C=27
B+2+B+B/2=27
4B=50
B=10.

Sanju said:   3 years ago
A = B+2.
C = B/2 (OR) B=2C.

WE KNOW THAT [A+B+C =27].
(B+2)+B+(B/2)=27,
2B+4+2B+B=54,
5B =54-4,
5B=50,
B=50/5,
B=10.
(10)

Onkar said:   6 years ago
A+B+C=27 --->(1)
A-B=2.
B=2C.
A-2C=2 --> (2).

SUBTRACT eqn 1 from 2 .
B + 3C = 25.
BUT B = 2C C = 5.
B = 10 A = 12.

Sam said:   5 years ago
Let.

C's age = x,
B's age = 2x,
A's age = 2x + 2.

X +2x+ 2x+2=27.
5x +2=27,
5x =25,
X=5.
B's Age= 2x.
2*5 = 10.
(7)

Saro said:   9 years ago
A = 2 + B,

B = 2C,

A + B + C = 27.

So, (2 + B) + B + B/2 = 27,

2B + B/2 = 25,

5B/2 = 25,

B = 10.

Sowji budigi said:   7 years ago
C is x.
B is 2x,.
A is 2x+2.
2x+2+2x+x=27.
5x+2=27.
5x=25.
X=5.
Then, B age is 2x so, 2*5=10.

Maddy said:   1 decade ago
Hi guys! can anyone tell me how to consider "x" in these questions and father son type ques?


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