Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 4)
4.
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
Answer: Option
Explanation:
Let C's age be x years. Then, B's age = 2x years. A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age = 2x = 10 years.
Discussion:
79 comments Page 2 of 8.
Vignesh venkatesan said:
1 decade ago
@Sri
b is twice old as c means.. c=b/2
b=2c
b is twice old as c means.. c=b/2
b=2c
Wisdom said:
1 decade ago
a=x;
b=x-2;
c=(x-2)/2;
a+b+c=27
x+x-2+[(x-2)/2]=27
[2x+2x-4+x-2]/2=27
5x-6=54
5x=60
x=12
b=x-2;
b=10 we got answer
b=x-2;
c=(x-2)/2;
a+b+c=27
x+x-2+[(x-2)/2]=27
[2x+2x-4+x-2]/2=27
5x-6=54
5x=60
x=12
b=x-2;
b=10 we got answer
Sathya said:
1 decade ago
Why we take c=x. Why we not take that a=x;.
Please explain.
Please explain.
Swetha said:
1 decade ago
@Sathya
We can take a = x also.
Whatever we take, answer 'll be same.
We can take a = x also.
Whatever we take, answer 'll be same.
Jatinder s said:
1 decade ago
A=B+2....1 given
B=2C .......2 given
from statement 2 : C=B/2
total is 27
therefor
A+B+C=27
B+2+B+B/2=27
4B=50
B=10.
B=2C .......2 given
from statement 2 : C=B/2
total is 27
therefor
A+B+C=27
B+2+B+B/2=27
4B=50
B=10.
Srini said:
1 decade ago
Can you give me short cut to solve this?
Arokiaraj said:
1 decade ago
c=x
b=2x
a=2x+2
(2x+2)+2x+x=27
5x=25
x=25/5
x=5
b=2x
b=2*5=10
b=2x
a=2x+2
(2x+2)+2x+x=27
5x=25
x=25/5
x=5
b=2x
b=2*5=10
Nagendra said:
1 decade ago
The population of town was 24000. If males increases by 6% and females by9%, it becomes 25620. Number of males and females are?- Please any one explain me...
NARESH said:
1 decade ago
Hi dude............
females(Y)=6000,males(X)=18000
x+y=24000........................(1)
(106/100)x+(109/100)y=25620.......(2)
by solving this 2 u get before increasing values..........
after increasing total number of females are (109/100)*6000=6540
after increasing total number of males are (106/100)*18000=19080
total is 25620
Hence proved(any doubts?)
females(Y)=6000,males(X)=18000
x+y=24000........................(1)
(106/100)x+(109/100)y=25620.......(2)
by solving this 2 u get before increasing values..........
after increasing total number of females are (109/100)*6000=6540
after increasing total number of males are (106/100)*18000=19080
total is 25620
Hence proved(any doubts?)
Renu said:
1 decade ago
A+B+C=27
(B+2)+B+(B-2)=27
3B=27
B=9
(B+2)+B+(B-2)=27
3B=27
B=9
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers