Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 7)
7.
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?
Answer: Option
Explanation:
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
| Then, | (6x + 6) + 4 | = | 11 |
| (5x + 6) + 4 | 10 |
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar's present age = (5x + 6) = 16 years.
Discussion:
128 comments Page 5 of 13.
Saesha said:
1 decade ago
Hi @Satyajeet.
It'll be (6x+6)+4/(5x+6)+4 = 11/10 because before 6 years the ratio was 6:5 but here we are taking after 4 yrs of present i.e past of 6 yrs + 4yrs (from present).
So it (6x+6)+4/(5x+6)+4 = 11/10.
It'll be (6x+6)+4/(5x+6)+4 = 11/10 because before 6 years the ratio was 6:5 but here we are taking after 4 yrs of present i.e past of 6 yrs + 4yrs (from present).
So it (6x+6)+4/(5x+6)+4 = 11/10.
KSRAJA said:
6 years ago
Here, first, understand the question.
6year ago, the ratio of the ages of Kunal and Sagar was 6 : 5. --> it means that ration of both is given for 6years ago.
So that, the present age is 6x+6 and 5x+6.
6year ago, the ratio of the ages of Kunal and Sagar was 6 : 5. --> it means that ration of both is given for 6years ago.
So that, the present age is 6x+6 and 5x+6.
Mounika said:
1 decade ago
Six years ago : x-6/y-6 = 5/6.
5x-30 = 6y-36.
5x-6y = -6-----equation 1.
Four years after: x+4/y+4 = 11/10.
10x-11y = 11y+44.
10x-11y = 4------equation 2.
By solving equations 1 and 2 we get y = 16.
5x-30 = 6y-36.
5x-6y = -6-----equation 1.
Four years after: x+4/y+4 = 11/10.
10x-11y = 11y+44.
10x-11y = 4------equation 2.
By solving equations 1 and 2 we get y = 16.
Kanchana Pandian said:
1 decade ago
Lets take Kunal and Sagar's age as x & y.
6 years ago, x-6/y-6 = 6/5 --> 5x-6y+6 = 0 -> A.
4 years hence, x+4/y+4 +11/10 --> 10x-11y-4 = 0 ->B.
Solve A & B,
y(Sagars age) = 16.
6 years ago, x-6/y-6 = 6/5 --> 5x-6y+6 = 0 -> A.
4 years hence, x+4/y+4 +11/10 --> 10x-11y-4 = 0 ->B.
Solve A & B,
y(Sagars age) = 16.
Priyanka said:
9 years ago
8 years ago Bhanu age was four greater than Ravi age that time also of the ratio of Ravi age to Bhanu 8 years after will be 6:7 find the ratio of Ravi age to that of Bhanu age 4 years after.
Lara said:
1 decade ago
Well in question they mentioned six years ago! so (6x+6) / (5x+6).
But they didn't mention that after 4 years from present age or from six years ago I hope the data given is insufficient.
But they didn't mention that after 4 years from present age or from six years ago I hope the data given is insufficient.
Shanky said:
1 decade ago
Want to know if 6 years ago ratio of age is taken as 6x and 5x.
Then at last why ratio of age is taken only 11 and 10 in equation.
Its the ratio of age so should be taken as 11x and 10x.
Then at last why ratio of age is taken only 11 and 10 in equation.
Its the ratio of age so should be taken as 11x and 10x.
Vicky said:
1 decade ago
They have mentioned that 6 years ago the ratio will be 6x+6/5x+6=6:5 and taking present age as a reference after 4 years the ratio is 6x+6+4/5x+6+4=11:10 So the answer will be 16 years.
Sarbajeet said:
9 years ago
All I understand but here the equation says 6 years ago and not after 6 years then how it can be x + 6. Can you explain why it could not be x - 6 when the question states the word 'ago'?
Karin said:
1 decade ago
We are supposed to calculate his present age so before 6 years his age be (6x) so after 6 years his age turns to (6x+6). They also mentioned four years hence so it is (6x+6) + 4.
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