Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 7)
7.
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?
Answer: Option
Explanation:
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
| Then, | (6x + 6) + 4 | = | 11 |
| (5x + 6) + 4 | 10 |
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar's present age = (5x + 6) = 16 years.
Discussion:
128 comments Page 4 of 13.
Anti Math said:
3 years ago
Try this shortcut guys;
6:5 x 11:10 ===>cross multiplication via fractions or distributive property.
You will get.. 60:55 or 12:11 // now add this to the current age ratio which is 6:5.
you will now get their age, and that is 18 :16 which means, Sagar's age is 16.
6:5 x 11:10 ===>cross multiplication via fractions or distributive property.
You will get.. 60:55 or 12:11 // now add this to the current age ratio which is 6:5.
you will now get their age, and that is 18 :16 which means, Sagar's age is 16.
(61)
Mit Patel said:
5 years ago
Present ages of Kunal is x and sagar is y.
Six years ago,
X-6/y-6=6/5.
After solving this equation I get,
5x-6y=-6.
And 4 year hence,
X-2/y-2=11/10.
After solving this equation I get,
10x-11y=-2.
Now solving this two-equation.
Sagar age is 10 year at present.
Six years ago,
X-6/y-6=6/5.
After solving this equation I get,
5x-6y=-6.
And 4 year hence,
X-2/y-2=11/10.
After solving this equation I get,
10x-11y=-2.
Now solving this two-equation.
Sagar age is 10 year at present.
(1)
Swapnil Jain said:
1 decade ago
Put it this way. The ratio of their ages 6 years ago was 6:5 and then come 6 year ahead to present time so there will be an addition of 6 years and then from this present moment again moving 4 years ahead that means adding 4 years. Hence the two additions.
Mayur baviskar said:
6 years ago
Let, Kunal present age = x.
& Sagar present age = y.
STEP1
6yr ago
(x-6)/(y-6)=6/5
5x-6y=-6 .----> eq(1)
STEP2:
4yr hence;
(x+4)/(y+4)=11/10.
10x-11y=4 ---->eq(2).
Solving eq. Simultaneously.
x=18 & y = 16.
Hence Sagar age is 16yr old.
& Sagar present age = y.
STEP1
6yr ago
(x-6)/(y-6)=6/5
5x-6y=-6 .----> eq(1)
STEP2:
4yr hence;
(x+4)/(y+4)=11/10.
10x-11y=4 ---->eq(2).
Solving eq. Simultaneously.
x=18 & y = 16.
Hence Sagar age is 16yr old.
Giri said:
1 decade ago
I dont think what vinod said is right....
Faruk has clearly explained...6 years
hence i.e.,6 yrs before the ages pf kunal and sagar is 6x and 5x respectively...
So present ages of both are 6x+6 and 5x+6(since present,add 6 years)..you'11 get it..
Faruk has clearly explained...6 years
hence i.e.,6 yrs before the ages pf kunal and sagar is 6x and 5x respectively...
So present ages of both are 6x+6 and 5x+6(since present,add 6 years)..you'11 get it..
Supriya said:
6 years ago
6:5 cross multiple both ratios.
11:10(difference)= 1 * 10 (time between ratios)
55 ~60 = 5
So if 5= 10.
1=5.
Now multiple with the past age ration you will get;
K = 12 , S=10.
And for Sagar's present age add 6yrs you will get 16 years.
11:10(difference)= 1 * 10 (time between ratios)
55 ~60 = 5
So if 5= 10.
1=5.
Now multiple with the past age ration you will get;
K = 12 , S=10.
And for Sagar's present age add 6yrs you will get 16 years.
Wasiq pirzada said:
9 years ago
It's very easy First look at the first sentence there is mentioned "6 years ago" ok Fine but the main thing is present 6 years ago means (-6) and 4 years hence will be aftter 4 from present a total of 10 should be added instead of +6 and +4.
Gunjan said:
4 years ago
@Khaisar.
The correct answer after solving it was:
(6x+6)+4/(5x+6)+4. = 11/10.
(6x+6)+4.
10(6x+10) = 11(5x+10),
60x+100 = 55x+110,
60x-55x = 110-100,
5x = 10,
x = 10÷2,
x = 5.
Sugar current age = 5x + 6,
= 10+6,
= 16.
Answer=16
The correct answer after solving it was:
(6x+6)+4/(5x+6)+4. = 11/10.
(6x+6)+4.
10(6x+10) = 11(5x+10),
60x+100 = 55x+110,
60x-55x = 110-100,
5x = 10,
x = 10÷2,
x = 5.
Sugar current age = 5x + 6,
= 10+6,
= 16.
Answer=16
(2)
Sumita said:
2 decades ago
In case of "ago" we always subtract the number of year.. But in the given answer.. its wrong I think.... as in next question on page 3 in case of "ago"... you also subtract the number of years.
Sindhu said:
1 decade ago
Let present ages of kunal and sagar be k and s respectively.
Then 6 years ago (k-6)/(s-6) = 5/6.
After 4 years (k+10/s+10) = 11/10.
After solving I got sagars age as 8 years. What wrong in this? Please help me.
Then 6 years ago (k-6)/(s-6) = 5/6.
After 4 years (k+10/s+10) = 11/10.
After solving I got sagars age as 8 years. What wrong in this? Please help me.
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