Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 7)
7.
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?
Answer: Option
Explanation:
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
| Then, | (6x + 6) + 4 | = | 11 |
| (5x + 6) + 4 | 10 |
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar's present age = (5x + 6) = 16 years.
Discussion:
128 comments Page 6 of 13.
Anil k said:
9 years ago
Here Kunal : Sagar
6x + 6 + 4: 5x + 6 + 4.
11 : 10.
Cross multiplication
60x + 100 = 55x + 110.
5x = 10.
x = 2 so Sagar present age is 5x + 6.
Here x = 2. So 5 * 2 +6 = 16.
6x + 6 + 4: 5x + 6 + 4.
11 : 10.
Cross multiplication
60x + 100 = 55x + 110.
5x = 10.
x = 2 so Sagar present age is 5x + 6.
Here x = 2. So 5 * 2 +6 = 16.
REVAT said:
9 years ago
After getting x=2.
In Q, we have to calculate the present age of Sagar.
Why it's 5x+6?
Is it 6 years ago na?
It must be.
5x = 5 (2) =10.
I'm confused someone help me.
In Q, we have to calculate the present age of Sagar.
Why it's 5x+6?
Is it 6 years ago na?
It must be.
5x = 5 (2) =10.
I'm confused someone help me.
Kanakareddy said:
1 decade ago
Age n years ago means = x-n.
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then, (6x+6)+4 = 11/(5x+6)+4 = 10.
Why you add the 6x+6, 5x+6.
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then, (6x+6)+4 = 11/(5x+6)+4 = 10.
Why you add the 6x+6, 5x+6.
Imran Ali said:
1 decade ago
@Fakrudin.
His son's age will be 15 year, please comment is am right or wrong. Thanks. If am wrong then please explain if I am right then I will be explain. Thanks.
His son's age will be 15 year, please comment is am right or wrong. Thanks. If am wrong then please explain if I am right then I will be explain. Thanks.
Zard said:
8 years ago
Anwser is E.
Because the given ratio not verified.
let present age 16 years after five years 21 (16+5).
21 not multiple of 10.
and also 16 not multiple of 5.
Because the given ratio not verified.
let present age 16 years after five years 21 (16+5).
21 not multiple of 10.
and also 16 not multiple of 5.
Faruk said:
2 decades ago
It is clearly said that 6 years ago their age was 6:5, so and hence their present age will be (6x+6)/(5x+6) and hence after 4 years you have to add another 4.
Jasika said:
1 decade ago
(x-6)/(y-6)=6/5......as 6 years ago ratio is 6/5
(x+4)/(y+4)=11/10...as after 4 years ratio is 11/10
by solving by solving y=4 years...den why it is wrong?
(x+4)/(y+4)=11/10...as after 4 years ratio is 11/10
by solving by solving y=4 years...den why it is wrong?
Sangay Wangchuk said:
5 years ago
@Swanali.
6 is added because it clearly says that six years ago their age was 6:5. And we are asked to find present ages so we have to add 6 on their age.
6 is added because it clearly says that six years ago their age was 6:5. And we are asked to find present ages so we have to add 6 on their age.
(2)
Ronak said:
1 decade ago
Yes same here. They have clearly given in the important formula section that when statement contains the word "ago", have to subtract the number of years.
Jaspreet said:
1 decade ago
Lets sons age x and father y.
Then,
x+y = 60.
x-6 = 5(60-x) (put y=60-x).
6x = 306.
x = 306/6.
x = 51.
Son will be 60-51 = 9.
9+6 = 15 years hence.
Then,
x+y = 60.
x-6 = 5(60-x) (put y=60-x).
6x = 306.
x = 306/6.
x = 51.
Son will be 60-51 = 9.
9+6 = 15 years hence.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers