Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 7)
7.
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?
Answer: Option
Explanation:
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
| Then, | (6x + 6) + 4 | = | 11 |
| (5x + 6) + 4 | 10 |
10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar's present age = (5x + 6) = 16 years.
Discussion:
129 comments Page 5 of 13.
Madhu said:
1 decade ago
It makes me confuse. Here in the question said 6 years ago. It means deduction?
Swapnil Jain said:
1 decade ago
Put it this way. The ratio of their ages 6 years ago was 6:5 and then come 6 year ahead to present time so there will be an addition of 6 years and then from this present moment again moving 4 years ahead that means adding 4 years. Hence the two additions.
Sachin said:
1 decade ago
6 years ago means 6yr back. So how can we add 6 in first step? (6x+6/5x+6).
Sanjay said:
1 decade ago
Also why can't the age of sagar be 20 yrs at present, as we need to include 4 yrs from the question to get the age of sagar at present?
Vicky said:
1 decade ago
They have mentioned that 6 years ago the ratio will be 6x+6/5x+6=6:5 and taking present age as a reference after 4 years the ratio is 6x+6+4/5x+6+4=11:10 So the answer will be 16 years.
Manikanth said:
1 decade ago
For some questions we are taking ago as + sign and some questions we are taking -sign could you please explain which sign we have to take? and why?
Praveen said:
1 decade ago
Let the present of kunal=x ,& sagar =y.
Given 6 years ago their ratio is 6:5, here 6 years should be subtracted from their present age.
i.e.,
1) (x-6)/(y-6) = 6/5 -----(1).
Given 4 years later means nothing but 2 years ago from their present age (or) again they come back 4 years from ago 6 years.
2) (x-2)/(y-2) = 11/10 -----(2).
Solving (1) & (2) we get sagar age y=10.
After 6 years sagar age is,
y+6 = 10+6 = 16.
Given 6 years ago their ratio is 6:5, here 6 years should be subtracted from their present age.
i.e.,
1) (x-6)/(y-6) = 6/5 -----(1).
Given 4 years later means nothing but 2 years ago from their present age (or) again they come back 4 years from ago 6 years.
2) (x-2)/(y-2) = 11/10 -----(2).
Solving (1) & (2) we get sagar age y=10.
After 6 years sagar age is,
y+6 = 10+6 = 16.
Jaspreet said:
1 decade ago
Lets sons age x and father y.
Then,
x+y = 60.
x-6 = 5(60-x) (put y=60-x).
6x = 306.
x = 306/6.
x = 51.
Son will be 60-51 = 9.
9+6 = 15 years hence.
Then,
x+y = 60.
x-6 = 5(60-x) (put y=60-x).
6x = 306.
x = 306/6.
x = 51.
Son will be 60-51 = 9.
9+6 = 15 years hence.
Satyajeet said:
1 decade ago
The word ago means before. So, we should subtract.
Hence, the equation should be.
(6x-6)+4/(5x-6)+4 = 11/10.
Please, Explain me, if I am wrong.
Hence, the equation should be.
(6x-6)+4/(5x-6)+4 = 11/10.
Please, Explain me, if I am wrong.
Pankaj said:
1 decade ago
Hi @Neha and @Faruk can you please explain what is "x" here?
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