Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 7)
7.
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?
16 years
18 years
20 years
Cannot be determined
None of these
Answer: Option
Explanation:

Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.

Then, (6x + 6) + 4 = 11
(5x + 6) + 4 10

10(6x + 10) = 11(5x + 10)

5x = 10

x = 2.

Sagar's present age = (5x + 6) = 16 years.

Discussion:
128 comments Page 6 of 13.

Varun kumar said:   1 decade ago
@Any where ago means you have to subtract but here given mistake. If I am wrong then please explain me?

Shanky said:   1 decade ago
Want to know if 6 years ago ratio of age is taken as 6x and 5x.

Then at last why ratio of age is taken only 11 and 10 in equation.

Its the ratio of age so should be taken as 11x and 10x.

Sng said:   1 decade ago
Let the ages of kunal and sagar be x and y years respectively.

Then,(x-6)/(y-6) = 6/5.

=>x = (6y-6)/5.

Similarly; (x+4)/(y+4) = 11/10.

=>(6y-6+20)/(5y+20) = 11/10.

=>60y+140 = 55y+220.

=>5y = 80.

=>y = 16 years.

Therefore, sagar present age is 16 years.

Darshana said:   1 decade ago
Why we have added 6 years instead of deducting as it is given that 6 years ago?

Kishori SK said:   1 decade ago
6 years ago itself the ages are 6x, 5x respectively. Then hence 6 years it becomes 6x+6, 5x+6 right?

Ravi teja said:   1 decade ago
Six years ago means we have to deduct 6 from the current age but from the present age to after 4 years, they mentioned the ratio so.

From past 6 years we have to add 6 to come to present age and from present age we have to add 4. So total it will become like (x+6) i.e. is present and plus 4 i.e future.

So we get (x+6+4). Thats it.

Prabhakaran said:   1 decade ago
(m-6) = (n-6)(6/5) --> 1.
(m+4) = (n+4)(11/10) --> 2.

Equating, 'm' we get,
(n-6)(6/5) + 6 = (n+4)(11/10) - 4.

Then n = 16 = Sagar's age.

ROHIT said:   1 decade ago
Let present age of kunal and sagar is x and y. Now according to the question
six year ago the ratio of the ages of kunal and sagar was 6/5.

It means x-6/y-6=6/5. Now solve it and finally it is 5x-6y+6=0.....(1 equation).

Now four years after it means x+4/y+4=11/10. Now solve it and finally it is 10x -11y-4=0.....(2 equation).

Solve both equation 1 and 2. To solve firstly multiply the whole equation of 1 with 2 that is 10x-12y+12=0.

Now equate equation 1 and 2 that is 10x-11y-4=10x-12y+12. Finally y =16 which is the age of sagar at present.

I HOPE THIS SOLUTION WILL BE HELPFUL !

Yusuf said:   1 decade ago
These questions with their answers will play the crucial role to my ability.

Ankit Gupta said:   1 decade ago
Let Kunal's present age = x and Sagar's present age = y.

6 years ago, Kunal's age:Sagar's age = (x-6):(y-6).

Now ATQ, (x-6):(y-6) = 6:5,solving which we get equation as:5x-6y = -6. Lets consider it as eq.1.

Now again, after 4 years, Ratio will be (x+4):(y+4) which is given as 11:10.
Solving which we get equation as 10x-11y=4. Let it be eq.2.

Therefore the 2 eq. are,
5x-6y=-6. Eq.1.
10x-11y=4. Eq.2.

Multiplying Eq. 1 by 2,it is 10x-12y=-12.Let it be eq. 3.
Subtracting Eq. 3 by Eq. 2,

10x-11y-10x+12y=16.
Therefore y=16, i.e Sagar's age is 16 years.

I hope you all will get this.


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