Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 5)
5.
Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?
Answer: Option
Explanation:
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
Then, | 5x + 3 | = | 11 |
4x + 3 | 9 |
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x - 44x = 33 - 27
x = 6.
Anand's present age = 4x = 24 years.
Discussion:
77 comments Page 4 of 8.
Siddharth said:
8 years ago
@Srinath.
Let present ages of Ganguly and Sachin be x & y respectively.
Product of extremes = Product of means.
6(y-1)=7(x-1) &.
7(y+4)=8(x+4).
x= 31 and y= 36.
Let present ages of Ganguly and Sachin be x & y respectively.
Product of extremes = Product of means.
6(y-1)=7(x-1) &.
7(y+4)=8(x+4).
x= 31 and y= 36.
JAISON said:
8 years ago
SHORTCUT METHOD.
Since they are asking ANAND's present age the ratio for Anands present age is 4.
So check the options which go for 4 table.
24 goes for 4 so 24 is the answer.
Suppose the ask Anand's age 3 years later the ratio is 9 so 3 years later his age will be 27 since 27 is divisible by 9.
Since they are asking ANAND's present age the ratio for Anands present age is 4.
So check the options which go for 4 table.
24 goes for 4 so 24 is the answer.
Suppose the ask Anand's age 3 years later the ratio is 9 so 3 years later his age will be 27 since 27 is divisible by 9.
Aman Chawla said:
8 years ago
Calculation can be reduced by using components and dividend which is applied on ratio's on both sides of equals.
Here is the method -> num1/den1 = num2=den2.
-> APPLYING COMPONENDO AND DIVIDENDO ON BOTH SIDES.
-> (num1+den1)/(num1-den1) = (num2+den2)/(num2-den2).
So here it goes,
(5x + 3) / (4x +3) = 11/9,
using above method it reduces to below in one go,
(9x + 6) / x = 10,
=> x = 6.
The requires answer then would be 4*x (using given ratio) is 24(answer).
Here is the method -> num1/den1 = num2=den2.
-> APPLYING COMPONENDO AND DIVIDENDO ON BOTH SIDES.
-> (num1+den1)/(num1-den1) = (num2+den2)/(num2-den2).
So here it goes,
(5x + 3) / (4x +3) = 11/9,
using above method it reduces to below in one go,
(9x + 6) / x = 10,
=> x = 6.
The requires answer then would be 4*x (using given ratio) is 24(answer).
Vinay biranje said:
8 years ago
Sameer and Anand age ratio is 5:4.
After 3 years.
Sameer and Anand age ration is 11:9.
The diffrence between presnet and after age is 6 & 5.
After cross multiplying to the difference of ratios samerr age 5x = 5*5 = 25.
Anand age 4x =6*4 = 24.
That's it.
After 3 years.
Sameer and Anand age ration is 11:9.
The diffrence between presnet and after age is 6 & 5.
After cross multiplying to the difference of ratios samerr age 5x = 5*5 = 25.
Anand age 4x =6*4 = 24.
That's it.
Junaid said:
8 years ago
Let me make it simple for you guys.
First, solve make ratios then equation:
5:4, which is 5x for Sameer and 4x for Anand : 5x/4x.
Three years from now 5x+3/4x+3 =11/9, solving this equation you get x=4.
How put 4 back on x places which is 5(4)/4(4)= 30/24 you get,
Hence 30/24 divide by 6 you get 5/4 further if u add 3 years from now, which 33/27, divide it by 3 you get ratio of 11/9.
First, solve make ratios then equation:
5:4, which is 5x for Sameer and 4x for Anand : 5x/4x.
Three years from now 5x+3/4x+3 =11/9, solving this equation you get x=4.
How put 4 back on x places which is 5(4)/4(4)= 30/24 you get,
Hence 30/24 divide by 6 you get 5/4 further if u add 3 years from now, which 33/27, divide it by 3 you get ratio of 11/9.
Ajay said:
7 years ago
Four years back Sham's age was 3/4th of Ram's age that time. Four years from now, Sham's age would be 5/6th of Ram's age that time. What is Sham's age today?
Can anyone solve this?
Can anyone solve this?
Pandian thanikodi said:
7 years ago
@All.
Please tell me that how possible the age ration will change on years? if both are in 5/4 ratio means after three years they should be in 5/4 only, how possible to become 11/9.
Please tell me that how possible the age ration will change on years? if both are in 5/4 ratio means after three years they should be in 5/4 only, how possible to become 11/9.
Rahul deb said:
7 years ago
The ratio of the present age of a and b is 7:4 after 2 years their ages will be in the ratio of 5:3 what will be the ratio of A's age after 5 years to B's age now?
Can anyone solve this?
Can anyone solve this?
Sadiq said:
7 years ago
Why does 4x multiply by x = 6?
Kplakshmi said:
7 years ago
@ Sonu.
The ratio means short answer of fraction eg: 20/25 short answer is 4/5 so we can write in the form of 4x/5x.
~ the fraction of numerator and denominators are divided by the same number that's called x
P/Q=3x/4x(presentratio) Q's present age is 20.
4x =20 ; => x= 5.
after 5 years, (3x+5/4x+5) = 20/25.
Then the ratio is 4/5.
The ratio means short answer of fraction eg: 20/25 short answer is 4/5 so we can write in the form of 4x/5x.
~ the fraction of numerator and denominators are divided by the same number that's called x
P/Q=3x/4x(presentratio) Q's present age is 20.
4x =20 ; => x= 5.
after 5 years, (3x+5/4x+5) = 20/25.
Then the ratio is 4/5.
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