Aptitude - Problems on Ages - Discussion
Discussion Forum : Problems on Ages - General Questions (Q.No. 5)
5.
Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age in years?
Answer: Option
Explanation:
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
| Then, | 5x + 3 | = | 11 |
| 4x + 3 | 9 |
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x - 44x = 33 - 27
x = 6.
Anand's present age = 4x = 24 years.
Discussion:
78 comments Page 3 of 8.
Siddharth said:
9 years ago
@Srinath.
Let present ages of Ganguly and Sachin be x & y respectively.
Product of extremes = Product of means.
6(y-1)=7(x-1) &.
7(y+4)=8(x+4).
x= 31 and y= 36.
Let present ages of Ganguly and Sachin be x & y respectively.
Product of extremes = Product of means.
6(y-1)=7(x-1) &.
7(y+4)=8(x+4).
x= 31 and y= 36.
Vivek said:
9 years ago
Thanks for the given explanation.
Pandian thanikodi said:
8 years ago
@All.
Please tell me that how possible the age ration will change on years? if both are in 5/4 ratio means after three years they should be in 5/4 only, how possible to become 11/9.
Please tell me that how possible the age ration will change on years? if both are in 5/4 ratio means after three years they should be in 5/4 only, how possible to become 11/9.
Srinath said:
9 years ago
One year ago Ganguly and Sachin ages are in the ratio 6:7.4 years hence, the ratio of their ages will become 7:8. How old is Sachin?
Please give me the answer.
Please give me the answer.
Rajshri Dubey said:
9 years ago
The ages of Nelson and Michael are in the ratio 3:5. After 9 years, the ratio of their ages will become 3:4. What is the present age of Michael?
Please explain this.
Please explain this.
Vamshi said:
9 years ago
Why not 11x/9x?
Rahul said:
9 years ago
The ratio of A's age 3 years ago and B's age 5 years ago is 4 : 5. If A is 4 years younger than B then what is B's Present age?
Please tell me the solution.
Please tell me the solution.
Shyamala said:
9 years ago
I agree with @Agila.
Dileep Goli said:
10 years ago
Let the present ages of Sameer and Anand be X and Y.
Also given in question x and y are in the ratio 5 : 4 then, X/Y = 5/4 ---> eq [1]
After 3 years hence(later) & their ratios are = x + 3/y + 3 = 11 : 9.
9(x + 3) = 11(y + 3),
9x + 27 = 11y + 33,
9x - 11y = 6---> eq[2].
Ffrom eq [1], x = 5y/4 --> eq [3].
Substitute eq [3] in eq [2].
9(5y/4) - 11y = 6,
45y - 44y = 24,
1y = 24,
Then, y = 24. the present age of Anand(y) is 24.
Also given in question x and y are in the ratio 5 : 4 then, X/Y = 5/4 ---> eq [1]
After 3 years hence(later) & their ratios are = x + 3/y + 3 = 11 : 9.
9(x + 3) = 11(y + 3),
9x + 27 = 11y + 33,
9x - 11y = 6---> eq[2].
Ffrom eq [1], x = 5y/4 --> eq [3].
Substitute eq [3] in eq [2].
9(5y/4) - 11y = 6,
45y - 44y = 24,
1y = 24,
Then, y = 24. the present age of Anand(y) is 24.
Aman Verma said:
10 years ago
First, write the present ages of Sameer and Anand as 5 and 4 respectively.
Now after three years their ages are 11 and 9 respectively.
Now to find the age of Anand. You have to multiply the present age of Anand.
i.e. (4 * 3(11 - 9)) / (11 * 4 - 9 * 5).
You will get the requires age of Anand, where 3 is times of the year, 11 and 9 are the ages of Sameer and Anand after 3 years.
Now after three years their ages are 11 and 9 respectively.
Now to find the age of Anand. You have to multiply the present age of Anand.
i.e. (4 * 3(11 - 9)) / (11 * 4 - 9 * 5).
You will get the requires age of Anand, where 3 is times of the year, 11 and 9 are the ages of Sameer and Anand after 3 years.
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