Aptitude - Problems on Ages - Discussion

Discussion Forum : Problems on Ages - General Questions (Q.No. 9)
9.
At present, the ratio between the ages of Arun and Deepak is 4 : 3. After 6 years, Arun's age will be 26 years. What is the age of Deepak at present ?
12 years
15 years
19 and half
21 years
Answer: Option
Explanation:

Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,

4x + 6 = 26       4x = 20

x = 5.

Deepak's age = 3x = 15 years.

Discussion:
37 comments Page 4 of 4.

Gargee said:   6 years ago
By given information 4:3 = 4=20.
hence 20/4=5.
therefore 5*3=15(ans).
(1)

Pavi said:   5 years ago
Gud morning.

Arun: Deepak=4:3 [at present]
So,let=4x:3x.
Gn that after 6 years arun age is 26,
So,
4x = 26.
4X = 20.
X = 5.
Deepak age = 3x.
=3 * 5
=15.
(1)

Bini said:   2 years ago
Let x is age of arun and y is age of deepak

Since, X/Y =4/3
then 3X =4Y
Finally X = 4/3Y ---> Eqn 1

After 6 years age of arun will be 26,
X + 6 = 26 ----> Eqn 2
Substitute Eqn 1 into Eqn 2.
4/3Y + 6 = 26
4Y + 18/3 =26
4Y + 18 = 78,
4Y = 60.
Therefore Y = 15.
(2)

Shayan math said:   2 years ago
Deepak = 4x + 6 = 26.
= 26 - 6 = 20.
4x = 20.
x = 5.

Arun = 3x.
= 3 x 5.
= 15 (ANS).
(5)

Anke Lakshmi said:   2 years ago
Let Arun's age be =x.
Let Deepak's age be =y.

Given:
x/y = 4/3 ------->equation 1

After 6 years:
x + 6 = 26 ------> equation 2

Solving equations 1 and 2 we get,
20/y = 4/3.
4y = 60.
y = 15.
(6)

Bhanu said:   1 year ago
Let Arun's present age be 4x and Deepak's age be 3x.
4x + 6 = 26,
4x = 20,
x = 5.
Deepak present age = 3x = 3(5) = 15 years.
(2)

Varad kulkarni said:   5 months ago
Let Arun = A
Let Deepak = D

A/D = 3/4
4A - 3D = 0 ---------> (i)

After 6 years, Deepak.
D + 6 = 26.
thus D = 20.

Put this value of D in equation i.
thus , 4A = 60

Thus A = 15 years.


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