Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 7)
7.
In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
21
46
25
117
1
50
3
25
Answer: Option
Explanation:

Let S be the sample space and E be the event of selecting 1 girl and 2 boys.

Then, n(S) = Number ways of selecting 3 students out of 25
= 25C3 `
= (25 x 24 x 23)
(3 x 2 x 1)
= 2300.

n(E) = (10C1 x 15C2)
= 10 x (15 x 14)
(2 x 1)
= 1050.

P(E) = n(E) = 1050 = 21 .
n(S) 2300 46

Discussion:
54 comments Page 5 of 6.

Daniel ocen said:   3 months ago
I can't understand this, someone help me to get it.

Chandni said:   10 years ago
Can anybody tell me why are they using 25C3?

Kathir lee said:   9 years ago
@ Sanjana.

Thank you for the explanation.

Bhargavi said:   7 years ago
On which table 1050/2300 can be divisible?
(2)

Thanos said:   5 years ago
@Jay Lee Lord.

Thank You for your answer.

Mahesh babu said:   1 decade ago
Because he asked 10 girls (and) 15 boys.

Mary-ann said:   10 years ago
I can't understand someone help.

Yugesh said:   1 decade ago
Why do you multiply 24x25x23?

Prabhat said:   1 decade ago
Nice explanation sanjana.

Azly said:   9 years ago
Thank you! @Sanjana.


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