Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 7)
7.
In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
21
46
25
117
1
50
3
25
Answer: Option
Explanation:

Let S be the sample space and E be the event of selecting 1 girl and 2 boys.

Then, n(S) = Number ways of selecting 3 students out of 25
= 25C3 `
= (25 x 24 x 23)
(3 x 2 x 1)
= 2300.

n(E) = (10C1 x 15C2)
= 10 x (15 x 14)
(2 x 1)
= 1050.

P(E) = n(E) = 1050 = 21 .
n(S) 2300 46

Discussion:
54 comments Page 3 of 6.

Kuldeep said:   8 years ago
Thanks @Sanjana.

Shikha said:   8 years ago
I am not able to understand this answer please some one clear my doubt.

Mary-ann said:   10 years ago
I can't understand someone help.

Deel khus said:   8 years ago
@Prabhu.

They are multiplied bc.

The rule of calculating probability is that if getting a or b then we must be added the probability and if getting a and b then its probability must be multiplied.

Shekhar Gupta said:   8 years ago
To select boy and girls are mutually independent events. So they are multiplied.

Thanos said:   5 years ago
@Jay Lee Lord.

Thank You for your answer.

Daniel ocen said:   3 months ago
I can't understand this, someone help me to get it.

Annie said:   1 decade ago
@Abhi

Because we do not care about the order in which we pick the boys and girls.

Also, if you picked the boys and girls in a different order than the one you used, wouldn't it be a different answer? So we don't solve it like x/25 x y/24 x z/23

Priya said:   1 decade ago
@prabhu.

Even I have the same doubt. Can some intellectual person answer this?

Gnana said:   1 decade ago
I too have same doubt. Can any one clarify this, soon.


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