Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 8)
8.
In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?
Answer: Option
Explanation:
| P (getting a prize) = | 10 | = | 10 | = | 2 | . |
| (10 + 25) | 35 | 7 |
Discussion:
25 comments Page 1 of 3.
Saheeba batra said:
1 decade ago
Hi Amulya is the answer 1/10?
If yes then, first draw a hexagon ABCDEF, you will see that te only equilateral triangles than can be formed are ACE and FBD, order of the points wont matter as it leads to the same triangle.
Now the number of ways in which points can be chosen are 6c3.
So your answer is : 2/6c3.
If yes then, first draw a hexagon ABCDEF, you will see that te only equilateral triangles than can be formed are ACE and FBD, order of the points wont matter as it leads to the same triangle.
Now the number of ways in which points can be chosen are 6c3.
So your answer is : 2/6c3.
Vinay Rajagopal said:
1 decade ago
@Shree Hemalatha & @Abhijeet :
It is a very cleverly worded problem. The 1st sentence "In a lottery, there are 10 prizes and 25 blanks" implies that there are a total of 10 prizes plus (+) the 25 blanks so Total of 35 :-D
Therefore, solution would be 10 / 35 = 2 / 7!
It is a very cleverly worded problem. The 1st sentence "In a lottery, there are 10 prizes and 25 blanks" implies that there are a total of 10 prizes plus (+) the 25 blanks so Total of 35 :-D
Therefore, solution would be 10 / 35 = 2 / 7!
Prachi said:
9 years ago
Hello,
I want to tell an easy solution for this.
We have 10 prizes and 25 blanks
Total chits = 10 + 25 = 35,
Probability of getting a prize = 10/35,
= 2/7.
This is a very easy way to find out the correct answer.
I want to tell an easy solution for this.
We have 10 prizes and 25 blanks
Total chits = 10 + 25 = 35,
Probability of getting a prize = 10/35,
= 2/7.
This is a very easy way to find out the correct answer.
(11)
Victor said:
1 decade ago
Please I need help with this problem!
In a box of 10 electrical parts, 2 are defective. If two parts are chosen at random from the box without replacement, what is the probability that both are defective?
In a box of 10 electrical parts, 2 are defective. If two parts are chosen at random from the box without replacement, what is the probability that both are defective?
Ramalakshmi said:
8 years ago
Question is the probability of (getting prize).
Prize given is just 10.
So prob will be 10 divided by total(prize + nothing or blank)..that is out of 10 & 25.
Therefore 10/35 = 2/7.
Prize given is just 10.
So prob will be 10 divided by total(prize + nothing or blank)..that is out of 10 & 25.
Therefore 10/35 = 2/7.
(1)
UmaShankar said:
1 decade ago
n(s)=10c29(choosing two parts)
n(e)=10c1*9c1 (Becoz we are not replacing the part after selecting so first from 10 parts 1 is selected and from remaining 9 one is selected as 9c1)
n(e)=10c1*9c1 (Becoz we are not replacing the part after selecting so first from 10 parts 1 is selected and from remaining 9 one is selected as 9c1)
Garima gupta said:
1 decade ago
n(s)total nbr cases:35c1 = 10+25=35
event happen n(e):10c1=10
(for geting one price frm the nbr of possibilities)
probability =n(e)/n(s)
=10/35
=2/7
event happen n(e):10c1=10
(for geting one price frm the nbr of possibilities)
probability =n(e)/n(s)
=10/35
=2/7
Amulya said:
1 decade ago
Please I need help !
Three of six vertices of a rectangle hexagon are chosen at random. The possibility that the triangle with three vertices is equilateral equal to ?
Three of six vertices of a rectangle hexagon are chosen at random. The possibility that the triangle with three vertices is equilateral equal to ?
Sahil said:
4 years ago
See my problem is that why we have added prizes and blanks?
Why we are selecting from 35 samples instead of 25 samples?
My answer is 10/25. Correct me If I am wrong.
Why we are selecting from 35 samples instead of 25 samples?
My answer is 10/25. Correct me If I am wrong.
(9)
Sai said:
6 years ago
They are asking about the prize.
So, we taken the prize alone not blanks.
Prize is n(p)= 10.
No of possibilities = 35 which is prize and blanks.
= 10/35 = 3/7.
So, we taken the prize alone not blanks.
Prize is n(p)= 10.
No of possibilities = 35 which is prize and blanks.
= 10/35 = 3/7.
(3)
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