Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 1)
1.
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
1
2
2
5
8
15
9
20
Answer: Option
Explanation:

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.

P(E) = n(E) = 9 .
n(S) 20

Discussion:
107 comments Page 8 of 11.

Nithya Arun said:   8 years ago
How can we calculate the same problem with big numbers? i.e if tickets numbered 1-200.

Shailendra rathore said:   9 years ago
9/20 is the right answer, and thanks for explaining the answer in different ways.

Ganapathithanuja said:   2 years ago
If 15 is there then the answer is 1/2.

Am I right? Anyone, please explain.
(40)

Prawesh Pradhan said:   9 years ago
P(A) + P(B) - P(A and B).
6 + 4 - 1 = 9.
P(E) = n(E)/n(S).
P(E) = 9/20.

Kavya said:   6 years ago
@Uday,

15 is repeated.
And 5 is missing.
Anyway, the answer is correct.
(5)

Rahul said:   1 decade ago
@rach.

Hai rach I didn't get you. Can you please explain clearly.

Sreejith said:   1 decade ago
Hello Rach,

How did you get that as pi/4?

Or anybody else knows?

Dabir Masood said:   9 years ago
Yes I too agree that 1/2 is the correct answer for this question.
(1)

ABHISEK MUKHERJEE said:   1 decade ago
Use just simple probability formula,

P(A+B) = P(A)+P(B)-P(AB).

Shraddha said:   7 years ago
But why is the number 5 not considered? 5 is a multiple of 5!


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