Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 1)
1.
Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
1
2
2
5
8
15
9
20
Answer: Option
Explanation:

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.

P(E) = n(E) = 9 .
n(S) 20

Discussion:
107 comments Page 7 of 11.

Saiful Islam said:   1 decade ago
Actually, I don't understand your explanation boss. Please explain elaborately. How can it will be 9/20?

Shashi said:   8 years ago
Since the number of events are 20.

So possible events are {3,6,9,12,15,18,5,10,20}.
So answer is 9/20.

Goutam said:   8 years ago
9/20 is correct answer.
5 multiplies are 5,10,15,20.
3 multiplies are 3,9,12,15,18.

Answer = 9/20.

Abhishek tomar said:   3 years ago
15 is the multiple of 3 and 5. while question is about the multiple of 3 or 5 so, why not option C?
(9)

Anonymous said:   7 years ago
Why didnt we apply the (not A) formula?
i.e. (Not blue ball) = 1 - (blue ball).
= 1 - 2/7.
= 5/7.

Kavana said:   9 years ago
From 1 to 340, the probability of getting multiples of 8 and 5 is? Please answer this question.

Satyendra Shukla said:   1 decade ago
Answer will be 9/20, because 15 already be considered, so it can not be consider next time.

Naana said:   1 decade ago
Please how do you come about the 1/2 (ie A intersection B) ? I am a bit confused.
Thanks.

Ephrem Alemu Mantose ETH said:   2 years ago
The answer is correct.
P(A U B) = P(A) + P(B) - P(AnB),
= 6/20 + 4/20 - 1/20,
= 9/20.
(18)

Veeru said:   1 decade ago
Sundar & Manju thought wrong because 15 already be consider.

So ans will be 9/20.
(1)


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