# Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 1)

1.

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?

Answer: Option

Explanation:

Here, S = {1, 2, 3, 4, ...., 19, 20}.

Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.

P(E) = | n(E) |
= | 9 | . |

n(S) |
20 |

Discussion:

101 comments Page 1 of 11.
PURVA said:
2 months ago

@All.

Here is my solution.

P(A or B) = P(A) + P(B) -P(A AND B).

P(3) = 6/20 {3,6,9,12,15,18},

P(5) = 4/20 {5,10,15,20},

P(3 and 5) = 1/20 {15}.

Here is my solution.

P(A or B) = P(A) + P(B) -P(A AND B).

P(3) = 6/20 {3,6,9,12,15,18},

P(5) = 4/20 {5,10,15,20},

P(3 and 5) = 1/20 {15}.

(4)

Sriram said:
3 months ago

The multiple of 3 and 5 is given numbers 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,7,18,19,20. While the question is about the multiple of 3 is 3,6,9,12,15,18 and the multiple of 5 is 5,10,15,20.

The total number is 10.

So,

10/20 = 1/2.

The total number is 10.

So,

10/20 = 1/2.

(5)

Abhishek tomar said:
10 months ago

15 is the multiple of 3 and 5. while question is about the multiple of 3 or 5 so, why not option C?

(3)

Niraml said:
11 months ago

Here, the total ticket is 20 we gonna take 1 from that 20 tickets it can be multiple of 3 or 5

so,

5C1 + 3C1/20C1 = 5+3/20 = 8/20.

= 2/5 is correct.

so,

5C1 + 3C1/20C1 = 5+3/20 = 8/20.

= 2/5 is correct.

Avaneet Agrahari said:
3 years ago

Multiple of 3=[,3,6,912,15,18]=6

M....o. 5=[5,10,15,20]=4 but 15 is already in 3 so it count 3

Ans= 6+3/20=9/20

M....o. 5=[5,10,15,20]=4 but 15 is already in 3 so it count 3

Ans= 6+3/20=9/20

(3)

Kavya said:
3 years ago

@Uday,

15 is repeated.

And 5 is missing.

Anyway, the answer is correct.

15 is repeated.

And 5 is missing.

Anyway, the answer is correct.

(3)

Kousalya said:
3 years ago

Yes, I too agree 1/2 is the right answer.

Uday said:
4 years ago

(3, 6,9,12,15,18,5,10,15,20).

= 10/20,

= 1/2.

= 10/20,

= 1/2.

Shivu said:
4 years ago

Ans is 9/20 because;

Multiple of 3 (3 6 9 12 15 18)=possiblity 6 so 6/20,

Multiple of 5 (5 10 15 20)=possibility 4 so 4/20,

15 is both sides so eliminate, so -1/20.

6/20+4/20-1/20 = 9/20.

Multiple of 3 (3 6 9 12 15 18)=possiblity 6 so 6/20,

Multiple of 5 (5 10 15 20)=possibility 4 so 4/20,

15 is both sides so eliminate, so -1/20.

6/20+4/20-1/20 = 9/20.

(2)

Anitha said:
4 years ago

@Shraddha.

5 is also considered so that we get probability 9/20. If 5 is not considered we can't get 9/20.

5 is also considered so that we get probability 9/20. If 5 is not considered we can't get 9/20.

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