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Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 6)
Probability
6.
Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
1
2
3
4
3
8
5
16
Answer: Option
Explanation:

In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.

Then, E = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4),
     (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1),
     (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}

n(E) = 27.

P(E) = n(E) = 27 = 3 .
n(S) 36 4

Discussion:
67 comments Page 5 of 7.
Scalar said:   9 years ago
Shouldn't the answer be 1/2?

The solution lists odd combinations, such as 4 and 1.
BHARATH said:   9 years ago
@Shubhankar & @Sabyasachi.

Thanks for giving an easy method to understand.
Naren said:   9 years ago
It may be also a short method:

Odd no 1st dice 1, 3, 5 = 3. 2nd dice odd no 1, 2, 3 = 3 hence 3 * 3 = 9.
Therefore, the product of even no 1-9/36 = 34.
Pravin atrekar said:   9 years ago
Wrong answer is mentioned here because we have to find the product not sum who's output comes even so and 9/35 =1/4.
Priya said:   8 years ago
@Shubhanka.

I can't understand your method. Can you explain it in detail?
Panging said:   8 years ago
How n(E) got =27?
Krishna said:   8 years ago
Sum of (4, 1), (4, 3), (4, 5) and so on in where ever even and add exit, the sum of two numbers becomes odd, but not even 4+1=5. So on with rest.
Naveena said:   8 years ago
I can't understand it please explain this problem.
Zaheer said:   8 years ago
Is there any shortcut method to solve such types of question.
Anusuya said:   8 years ago
I don't understand why take product why only take sum?

Please, guys explain.
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