Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 5)
5.
Three unbiased coins are tossed. What is the probability of getting at most two heads?
3
4
1
4
3
8
7
8
Answer: Option
Explanation:

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P(E) = n(E) = 7 .
n(S) 8

Discussion:
121 comments Page 4 of 13.

Pravin patel said:   1 decade ago
@LETTISHA.

Possibility is head or tail, mean 2 time.

And it is to 3 time means 2^3 = 8(2*2*2) = 8.

Hear is coin, if we are using dies then 6^3.

Manan said:   1 decade ago
Can't it be like this:

Probability of all events = 3 heads, 2 heads, 1 head, 0 heads.

Hence n(s) = 4.
n(e) = 3.
Probability = 3/4.

Sonali malviya said:   1 decade ago
Can anybody tell me why we have taken n(e) = 7?

Ghanshyam said:   1 decade ago
How P(E) = n(E) upon n(S)= 7 by 8.

Riems said:   1 decade ago
Is there any direct method for calculating it? Because calculating n(e) may get confused in the exams time.

Brian said:   1 decade ago
What is the probability of this question?

Joel said:   1 decade ago
At most 2 heads, so how did you include HHH?

Venkat said:   1 decade ago
Answer is 3/8 i.e. (C).

H T H.
H H T.
T H H.

Rajesh said:   1 decade ago
At most means 7/8.

At leat means 3/8.

Manu said:   1 decade ago
Thanks very helpful.


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