Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 5)
5.
Three unbiased coins are tossed. What is the probability of getting at most two heads?
Answer: Option
Explanation:
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
 P(E) = |
n(E) | = | 7 | . |
| n(S) | 8 |
Discussion:
111 comments Page 1 of 12.
Shobha said:
1 week ago
I don't understand this logic - Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
As this question says event of getting at most two heads.
It should be these combinations- THH, HTH, HHT, HHH.
Please, someone, explain.
As this question says event of getting at most two heads.
It should be these combinations- THH, HTH, HHT, HHH.
Please, someone, explain.
Triveni said:
3 weeks ago
I can't Understand this. Anyone, please help me to get this.
Amit Verma said:
3 months ago
Here S = {TTT, TTH, THT, THH, HHH, HHT, HTH, HTT}
Let E = Even of getting at most two heads.
Then E = {HHH, HHT, HTH, THH},
P(E) = n(E)/n(S),
= 4/8 = 1/2.
Let E = Even of getting at most two heads.
Then E = {HHH, HHT, HTH, THH},
P(E) = n(E)/n(S),
= 4/8 = 1/2.
(9)
Tejeshwari said:
9 months ago
Thanks all for explaining it.
(2)
Zahid said:
1 year ago
How to find the events of coins quickly like TTT and HHT etc? explain me.
(1)
MUKESH MAHLI said:
2 years ago
At most mean- less than or less than equal to.
Am I right?
Am I right?
Dhivya said:
2 years ago
Thank you for explaining @Sundar.
Sumanth said:
3 years ago
It is 6/8=3/4.
(1)
Meena said:
3 years ago
The question is what is the probability of getting "at most" two heads?
Here, at most two heads mean Not more than two heads.
So, HHH is more than two heads. It is not counted in Event. Am I right?
Here, at most two heads mean Not more than two heads.
So, HHH is more than two heads. It is not counted in Event. Am I right?
(2)
Neeraja said:
3 years ago
@ Vivek Rai.
A coin is tossed 3 times. We have 8 possible outcomes. In those 8 possible outcomes, we should choose the outcomes in which we have 1 head, 2 heads or no heads (3tails). But according to you if you consider the only head side of the coin then how did you get 8 in the denominator?
So the answer is 7/8.
A coin is tossed 3 times. We have 8 possible outcomes. In those 8 possible outcomes, we should choose the outcomes in which we have 1 head, 2 heads or no heads (3tails). But according to you if you consider the only head side of the coin then how did you get 8 in the denominator?
So the answer is 7/8.
(3)
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers