Aptitude - Probability - Discussion

Discussion Forum : Probability - General Questions (Q.No. 5)
5.
Three unbiased coins are tossed. What is the probability of getting at most two heads?
3
4
1
4
3
8
7
8
Answer: Option
Explanation:

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P(E) = n(E) = 7 .
n(S) 8

Discussion:
122 comments Page 1 of 13.

Abdul Wahab said:   2 weeks ago
We can answer this question by using the Binomial Distribution.

3 x 1/4 x 1/2 = 3/8.

Gech said:   8 months ago
It must be 3\8.
(10)

Chinmay Gawane said:   1 year ago
3/8 is the right answer.
(20)

Reena said:   2 years ago
At most 2 heads means it cannot be more than 2. It can be zero or 1 or 2 but not 3. And there is only one case that have 3 (HHH). So probability is 7/8.
(54)

Ragini said:   2 years ago
The right Answer is 3/8.
(12)

Ismail said:   2 years ago
"At most 2 head" means a maximum 2 no. of heads that is there can be 0 heads,1 head or 2 heads.
So, TTT, TTH, THT, THH, HTT, HHT, HTH have at most 2 heads.
So, n(E)=7 & n(S)= 8 ---> n(E)/n(S) = 7/8.
(14)

Sowmya said:   2 years ago
The Answer should be 3/8.
(5)

Manisha Yadav said:   2 years ago
The right answer should be 3/8.
(15)

Chelsia said:   2 years ago
We can get quickly the number of events like 2 to the Power of (number of coins).

I.e 2'3=> 8.
(7)

Asmi said:   2 years ago
At most means not more than 2 heads.

And at least means more than 2 heads.
(24)


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