Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 5)
5.
Three unbiased coins are tossed. What is the probability of getting at most two heads?
Answer: Option
Explanation:
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
 P(E) = |
n(E) | = | 7 | . |
| n(S) | 8 |
Discussion:
122 comments Page 13 of 13.
Gech said:
8 months ago
It must be 3\8.
(10)
Abdul Wahab said:
2 weeks ago
We can answer this question by using the Binomial Distribution.
3 x 1/4 x 1/2 = 3/8.
3 x 1/4 x 1/2 = 3/8.
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