Aptitude - Probability - Discussion
Discussion Forum : Probability - General Questions (Q.No. 5)
5.
Three unbiased coins are tossed. What is the probability of getting at most two heads?
Answer: Option
Explanation:
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
 P(E) = |
n(E) | = | 7 | . |
| n(S) | 8 |
Discussion:
121 comments Page 11 of 13.
Vivek Rai said:
5 years ago
But it says heads that mean only head should be counted not the tail side of the coin as we know a coin has 2 side head and tail and the question is asking about at most 2 heads so it should be = 3/8.
Anyone, please clarify my doubts.
Anyone, please clarify my doubts.
(3)
Neeraja said:
5 years ago
@ Vivek Rai.
A coin is tossed 3 times. We have 8 possible outcomes. In those 8 possible outcomes, we should choose the outcomes in which we have 1 head, 2 heads or no heads (3tails). But according to you if you consider the only head side of the coin then how did you get 8 in the denominator?
So the answer is 7/8.
A coin is tossed 3 times. We have 8 possible outcomes. In those 8 possible outcomes, we should choose the outcomes in which we have 1 head, 2 heads or no heads (3tails). But according to you if you consider the only head side of the coin then how did you get 8 in the denominator?
So the answer is 7/8.
(5)
Meena said:
5 years ago
The question is what is the probability of getting "at most" two heads?
Here, at most two heads mean Not more than two heads.
So, HHH is more than two heads. It is not counted in Event. Am I right?
Here, at most two heads mean Not more than two heads.
So, HHH is more than two heads. It is not counted in Event. Am I right?
(6)
Sumanth said:
5 years ago
It is 6/8=3/4.
(4)
Dhivya said:
4 years ago
Thank you for explaining @Sundar.
MUKESH MAHLI said:
4 years ago
At most mean- less than or less than equal to.
Am I right?
Am I right?
(4)
Zahid said:
4 years ago
How to find the events of coins quickly like TTT and HHT etc? explain me.
(5)
Tejeshwari said:
3 years ago
Thanks all for explaining it.
(2)
Amit Verma said:
3 years ago
Here S = {TTT, TTH, THT, THH, HHH, HHT, HTH, HTT}
Let E = Even of getting at most two heads.
Then E = {HHH, HHT, HTH, THH},
P(E) = n(E)/n(S),
= 4/8 = 1/2.
Let E = Even of getting at most two heads.
Then E = {HHH, HHT, HTH, THH},
P(E) = n(E)/n(S),
= 4/8 = 1/2.
(37)
Triveni said:
2 years ago
I can't Understand this. Anyone, please help me to get this.
(1)
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