Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 5)
5.
A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is:
Answer: Option
Explanation:
Suppose, first pipe alone takes x hours to fill the tank .
Then, second and third pipes will take (x -5) and (x - 9) hours respectively to fill the tank.
 |
1 | + | 1 | = | 1 |
| x | (x - 5) | (x - 9) |
 |
x - 5 + x | = | 1 |
| x(x - 5) | (x - 9) |
(2x - 5)(x - 9) = x(x - 5)
x2 - 18x + 45 = 0
(x - 15)(x - 3) = 0
x = 15. [neglecting x = 3]
Discussion:
69 comments Page 3 of 7.
Basavaraj said:
9 years ago
Why 1/x-9 Comes to negative?
(1)
Chandni said:
1 decade ago
I solved it by taking 2nd pipe's speed as x.
Then 1st pipe speed would be x-5 and 3rd pipe = x+4.
If we resolve now, we get y = -10 and y = 2.
So, I was finding answer according to 2.
Then 1st pipe speed would be x-5 and 3rd pipe = x+4.
If we resolve now, we get y = -10 and y = 2.
So, I was finding answer according to 2.
(1)
Pranesh kumar said:
2 decades ago
Why you neglect x=3 for what reasons?
(1)
Karthikeyan said:
2 decades ago
How got this equation 1/x+1/x-5=1/x-9 ?
(1)
Sachin said:
2 decades ago
How can a pipe fill in both 3 and 9 hours. Hows it possible?
Only one answer must be true?
which one how to get?
Only one answer must be true?
which one how to get?
(1)
Venky said:
1 decade ago
4 hours slower than the third pipe = means how we took 1/X-9 and that also like this 1/X +1/X-5= 1/X-9
third pipe speed we dont know ...the how {x-9}
third pipe speed we dont know ...the how {x-9}
Monu dhaka said:
9 years ago
@Lavanya.
Answer is 10 minutes {(18/24)+(8/32)}=1.
18-8 = 10minutes.
Answer is 10 minutes {(18/24)+(8/32)}=1.
18-8 = 10minutes.
Sana said:
9 years ago
Suppose, second pipe alone takes x hours to fill the tank.
Then, first pipe and third pipe will take (x + 5) and (x - 4) hours respectively to fill the tank.
1/(x+5) + 1/x = 1/(x-4)
( x + x + 5 ) / ( x^2 + 5x ) = 1/(x-4)
Srossmultiply ( 2x + 5 ) * ( x - 4 ) = 1 * (x^2 + 5x )
Solve, you get
(x - 10)(x + 2) = 0
x = 10. [neglecting x = -2]
1st pipe = x + 5 = 15 hours.
Then, first pipe and third pipe will take (x + 5) and (x - 4) hours respectively to fill the tank.
1/(x+5) + 1/x = 1/(x-4)
( x + x + 5 ) / ( x^2 + 5x ) = 1/(x-4)
Srossmultiply ( 2x + 5 ) * ( x - 4 ) = 1 * (x^2 + 5x )
Solve, you get
(x - 10)(x + 2) = 0
x = 10. [neglecting x = -2]
1st pipe = x + 5 = 15 hours.
SABYASACHI said:
1 decade ago
Is there any short tricks for this type of questions?
Pradhyumna said:
9 years ago
Can't we pick the 'B' to be as x and do the same things since When I did I got four first just by generally calculating it?
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