Aptitude - Pipes and Cistern - Discussion
Discussion Forum : Pipes and Cistern - General Questions (Q.No. 7)
7.
A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
Answer: Option
Explanation:
Suppose pipe A alone takes x hours to fill the tank.
| Then, pipes B and C will take | x | and | x | hours respectively to fill the tank. |
| 2 | 4 |
 |
1 | + | 2 | + | 4 | = | 1 |
| x | x | x | 5 |
 |
7 | = | 1 |
| x | 5 |
x = 35 hrs.
Discussion:
33 comments Page 4 of 4.
Aparna said:
1 decade ago
1/x+2/x+4/x = 7/x how is it possible?
Why don't we take x+2x+4X?
Can anyone explain me please?
Why don't we take x+2x+4X?
Can anyone explain me please?
Richa said:
1 decade ago
If B is half time as fast than A. Then B=2X?
Jayasankar said:
1 decade ago
Given condition,
b = 2a.
c = 4a(c=2b=2*2a=4a).
and a+b+c = 1/5(for one hour).
==> a+2a+4a = 1/5.
==> a = 1/35 (one hour work).
Total = 35.
b = 2a.
c = 4a(c=2b=2*2a=4a).
and a+b+c = 1/5(for one hour).
==> a+2a+4a = 1/5.
==> a = 1/35 (one hour work).
Total = 35.
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