Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 7)
7.
A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
20 hours
25 hours
35 hours
Cannot be determined
None of these
Answer: Option
Explanation:

Suppose pipe A alone takes x hours to fill the tank.

Then, pipes B and C will take x and x hours respectively to fill the tank.
2 4

1 + 2 + 4 = 1
x x x 5

7 = 1
x 5

x = 35 hrs.

Discussion:
33 comments Page 1 of 4.

Suganthi said:   1 decade ago
Please any one help me
B is twice as fast A means
A=X; B=2X isn't it
Then how B = X / 2 will come

Nitish said:   1 decade ago
As pipe C is twice as fast as B and B is twice as fast as A so if a fill the tank in x min.

As B is Two Time Faster not slower so it will take half time less than A that's why we have taken pipe B will fill in x/2 hours in less time compared to A.
(1)

Saina said:   1 decade ago
Thanku nitish.

Nick said:   1 decade ago
Why summation is in the form of 1/x + 2/x + 4/x?

It should be x + x/2 + x/4 ?

Isn't it?

Ajay said:   1 decade ago
The question is say that The pipe C is twice as fast as B and B is twice as fast as A i.e means A:B:C = x:2x:4x respectively then why you are take 1/x, 2/x, 4/x.

Harsh Londhe said:   1 decade ago
Try to understand question, question itself has answer.

Let A fill tank in x hrs.

Therefore tank filled in one hrs is 1/x.

And B pipe is twice than A means 2 (1/x).

C pipe is twice than B means 2 (2 (1/x) ) i.e 4/x.

1/x+2/x+4/x = 1/5.

7/x = 1/5.

x = 35 hrs.

Abhishek said:   1 decade ago
Why summation is not in this form?

X+x/2+x/4 = 1/5.

SABYASACHI said:   1 decade ago
@Abhishek. We are calculating per hour, that's why we are taking the reverse of (x, x/2, x/4)...

Usha said:   1 decade ago
1/x+2/x+4/x = 7/x. How it will possible?

Vikash Kumar Das said:   1 decade ago
As per the question we can solve as:
c=2b;-------->1.
b=2a;-------->2.

Also a+b+c=1/5(work done in 1 hour by a,b,c)--------?3.

Now substitute the value of c=2b and b=2a in 3.
So eqn.3 becomes a+2a+2b = 1/5.

Again substitute b=2a in place of b.
So eqn becomes 3a+4a = 1/5.

So solving we get the value of a = 1/35.
So that is d work done in 1 hr.
So total work done = 35.


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