Aptitude - Pipes and Cistern - Discussion

Discussion Forum : Pipes and Cistern - General Questions (Q.No. 7)
7.
A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
20 hours
25 hours
35 hours
Cannot be determined
None of these
Answer: Option
Explanation:

Suppose pipe A alone takes x hours to fill the tank.

Then, pipes B and C will take x and x hours respectively to fill the tank.
2 4

1 + 2 + 4 = 1
x x x 5

7 = 1
x 5

x = 35 hrs.

Discussion:
33 comments Page 3 of 4.

SABYASACHI said:   1 decade ago
@Abhishek. We are calculating per hour, that's why we are taking the reverse of (x, x/2, x/4)...

Vineeth said:   7 years ago
Considering the value of A as X, B as 2X and C as 4X. Can anybody help me in solving this ?
(2)

Nick said:   1 decade ago
Why summation is in the form of 1/x + 2/x + 4/x?

It should be x + x/2 + x/4 ?

Isn't it?

Rkay said:   2 years ago
R*T = w
(4+2+1) * 5 = w
7*5 = w
W = 35
An efficiency = 1
Time taken = 35/1 = 35.
(6)

Ritwik said:   6 years ago
B is twice as fast as A so if A=x, B=2x then how x/2?
(3)

Abhishek said:   1 decade ago
Why summation is not in this form?

X+x/2+x/4 = 1/5.

Richa said:   1 decade ago
If B is half time as fast than A. Then B=2X?

Laxmi said:   1 decade ago
Hi friends please tell how 1/5 is come here.

Usha said:   1 decade ago
1/x+2/x+4/x = 7/x. How it will possible?

Naveen chowdary said:   9 years ago
Why not it is 1/x + 1/2x + 1/4x = 1/5?


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